Answer:
a) P(X∩Y) = 0.2
b) 
= 0.16
c) P = 0.47
Step-by-step explanation:
Let's call X the event that the motorist must stop at the first signal and Y the event that the motorist must stop at the second signal.
So, P(X) = 0.36, P(Y) = 0.51 and P(X∪Y) = 0.67
Then, the probability P(X∩Y) that the motorist must stop at both signal can be calculated as:
P(X∩Y) = P(X) + P(Y) - P(X∪Y)
P(X∩Y) = 0.36 + 0.51 - 0.67
P(X∩Y) = 0.2
On the other hand, the probability that he must stop at the first signal but not at the second one can be calculated as:
= P(X) - P(X∩Y)
= 0.36 - 0.2 = 0.16
At the same way, the probability 
that he must stop at the second signal but not at the first one can be calculated as:
= P(Y) - P(X∩Y)
= 0.51 - 0.2 = 0.31
So, the probability that he must stop at exactly one signal is:
Answer:
(12,0), (3, -1) (0,-4/3)
Step-by-step explanation:
To do this problem, you have to plug in the x and y values. For example, the first one would be 12-9(0)=12, and so on.
Answer:
-36/7 or -5.14287
Step-by-step explanation:
so I would get rid of parentheses you do not need them
=
(because when two negative come before two numbers like -x-y they are being added but negative is present to the result of the sum, when one negative sign comes after a number and the other negative sign comes before a number, like x--y they are being added as well but negative is not present to the result of the sum)
-36/7=-5.1428
hope this helps!
Can barely see the questions ! Retake a picture if you can.
Answer:
<h2><em><u>
.1etc</u></em></h2>
Step-by-step explanation:
It would be 16 divided by 3 and from the answer you get from that you should divide it by itself equaling infinite .111111111111etc
