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3 years ago

52 4/9 plus 8 7/8 equals?

Mathematics

2 answers:

Natalka [10]3 years ago

6 0

The answer would be 61 23/72

IRINA_888 [86]3 years ago

4 0

First you need to find a common denominator, I'll use 72 so then it becomes:
52 32/72 + 8 63/72
Then I make them improper fractions so it becomes:
3776/72+639/72
Add them together and you have:
4415/72, this can be made into a mixed number:
61 23/72

Hope this helps :)

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3 years ago

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ANEK [815]

Answer:

The answer is below

Step-by-step explanation:

a) The equation of a line passing through the point (0,0) and (16,4) is given by:

$y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)\\\\y-0=\frac{4-0}{16-4}(x-0)\\\\y=\frac{1}{4}x$

We have to find the equation of the line perpendicular to y = (1/4)x and passing through the point (4,6).

The line perpendicular to y = (1/4)x has a slope of -4 (product of their slope = -1).

Hence:

$y- y_1=m(x-x_1)\\\\y-6=-4(x-4)\\\\y-6=-4x+16\\\\y=-4x+22$

The slope of a line passing through the point (16,4) and (4,6) is given by:

$m=\frac{y_2-y_1}{x_2-x_1}\\\\m=\frac{6-4}{4-16}=-\frac{1}{6}$

We have to find the equation of the line perpendicular to the line with slope of -1/6 and passing through the point (0,0).

The line perpendicular to a line with slope -1/6 has a slope of 6

Hence:

$y- y_1=m(x-x_1)\\\\y-0=6(x-0)\\\\y=6x$

Solving y = 6x and y = -4x + 22, gives:

x = 2.2, y = 13.2

Hence the orthocenter is at (2.2, 13.2)

The slope of a line passing through the point (3,4) and (11,12) is given by:

$m=\frac{y_2-y_1}{x_2-x_1}\\\\m=\frac{12-4}{11-3}=1$

We have to find the equation of the line perpendicular to the line with slope of 1 and passing through the point (8,15).

The line perpendicular to a line with slope 1 has a slope of -1

Hence:

$y- y_1=m(x-x_1)\\\\y-15=-1(x-8)\\\\y=-x+8+15\\\\y=-x+23$

The slope of a line passing through the point (11,12) and (8,15) is given by:

$m=\frac{y_2-y_1}{x_2-x_1}\\\\m=\frac{15-12}{8-11}=-1$

We have to find the equation of the line perpendicular to the line with slope of -1 and passing through the point (3,4).

The line perpendicular to a line with slope -1 has a slope of 1

Hence:

$y- y_1=m(x-x_1)\\\\y-4=1(x-3)\\\\y=x-3+4\\\\y=x+1$

Solving y = -x + 23 and y = x + 1, gives:

x = 11, y = 12

Hence the orthocenter is at (11, 12)

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3 years ago