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Ugo [173]
3 years ago
9

Find the slope. write in slope intercept form and point slope form. ​

Mathematics
1 answer:
MaRussiya [10]3 years ago
3 0

Answer:

1,4

Step-by-step explanation:

2 + 1 is 3. 3 + 4 is 7

3 + 1 is 4. 7 + 4 is 11. so it's 1 up and 4 across

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Round 20.92 to the nearest ten​
lisabon 2012 [21]

Answer:

20.9

Step-by-step explanation:

20.93

=20.9

8 0
3 years ago
What is the slope of the line that passes through the points (5,-25) and (10, -15)
Salsk061 [2.6K]
<h2>Answer:</h2>

All you need to do is use the slope formula: y₂ - y₁/x₂ - x₁.

\frac{-15 - (-25)}{10 - 5}\\\\\frac{10}{5} = 2

Always simplify the fraction!

4 0
3 years ago
What is <br> 1.567 + 2.345 - 1.83(5) A) -2,082 B) -5.238 C) 2.082 D) 5.742
ladessa [460]

Answer:

c) 2.082

Step-by-step explanation:

First you would add 1.567 and 2.345 together to get 3.912. If you take 3.912 and subtract 1.83 from that, it would be 2.082.

7 0
3 years ago
Read 2 more answers
8^3*8^-5*8^y=1/8^2, what is the value of y in the product of powers below?
Aleks04 [339]

For this case we have that by definition of multiplication of powers of the same base, the same base is placed and the exponents are added:

a ^ n * a ^ m = a ^ {n + m}

So, we can rewrite the given expression as:

8 ^ {3-5 + y} = \frac {1} {8 ^ 2}\\8 ^ {- 2 + y} = \frac {1} {8 ^ 2}

So, if y = 0:

8 ^ {- 2} = \frac {1} {8 ^ 2}\\\frac {1} {8 ^ 2} = \frac {1} {8 ^ 2}

Equality is met!

Answer:

y = 0

3 0
3 years ago
Read 2 more answers
A slide 4.3 m long makes an angle of 31 degrees with the ground how high is the top of the slide above the ground
tia_tia [17]
Given that the slide is 4.3 m long and makes an angle of 31°, then to get how high the slide is above the ground we use trigonometry formula.
sin θ=opposite/hypotenuse
opposite=x=how high the slide is above the ground
hypotenuse=length of the slide=4.3 m
θ=31°
plugging the values in the formula and solving for x we obtain
sin 31=x/4.3
x=4.3×tan 31
x=4.3(0.6009)
x=2.58387
x~2.6 m

Hence we conclude that the top of the slide is approximately 2.6 m from the ground

4 0
3 years ago
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