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alina1380 [7]
1 year ago
8

During a science experiment,the temperature of a solution in beaker 1 was 5 degrees below zero. The temperature of a solution in

Beaker 2 was the opposite of the temperature in beaker 1. What was the temperature in beaker 2?
A. - 5 degrees
B- 0 degrees
C- 5 degrees
D- 10 degrees
Mathematics
1 answer:
GaryK [48]1 year ago
7 0
Answer:
5 degrees

Step-by-step explanation:

We are given that during a science experiment
The temperature of a solution in a beaker 15 degrees below zero
The temperature of solution in a beaker 2 was opposite of the temperature in beaker 1
We have to determine the temperature of beaker 2.
It mean temperature of beaker 1 solution=-5 degrees
According to question
Temperature of beaker 2 solution =5 degrees
Hence, the temperature of solution in a beaker 2=5 degrees
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Write in y= mx + b form: a line through (-3,1) having the same y-intercept as the graph of x-2y=-4
MariettaO [177]

Step-by-step explanation:

Aight, so the same intercept

- 2y =  - 4 - x =  =  =  >  \\ y =  \frac{1}{2} x + 2

m=½

y =  \frac{1}{2} x + b =  =  =  >  \\ now \: let \: us \: replace \: the \: point \\ 1 =  \frac{1}{2} ( - 3) + b =  =  =  >  \\  \frac{5}{2}  = b

soooo

y =  \frac{1}{2} x +  \frac{5}{2}

7 0
2 years ago
Ax+3=23 if a=0 plz help
VladimirAG [237]

Answer:

x = \frac{23}{a}

Step-by-step explanation:

Given equation is,

ax + 3 = 23

To solve this equation for the value of x isolate the variable 'x' on the one side of the equation.

Step 1,

Subtract 3 from both the sides of the equation.

ax + 3 - 3 = 23 - 3

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Step 2,

Divide the equation by a,

\frac{ax}{a}=\frac{23}{a}

x = \frac{23}{a}

Therefore, x = \frac{23}{a} will be the answer.

6 0
3 years ago
What is the first geometric sequence below
ale4655 [162]
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If, on the other hand, you go backwards (terms decreasing), then you divide a term to find what the previous term was.

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5 0
3 years ago
Upvote an will mark brainlest
Irina18 [472]

Answer:heyyy there...the answer is b that is -12x^3+12x^2-20

Step-by-step explanation:

<h3>f(x)= -12x^3+19x^2-5</h3><h3>g(x)= 7x^2+15</h3><h3>f(x)-g(x)=(-12x^3+19x^2-5)-( 7x^2+15)...{while opening the bracket the sign of the second polynomial changes accordingly}</h3><h3>it becomes -12x^3+19x^2-5-7x^2-15</h3><h3>=-12x^3+12x^2-20</h3><h3>HOPE IT HELPED UUUU</h3>
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3 years ago
Hope someone can help me with this
sergeinik [125]

That would be Nets 1, 4 and 5.

6 0
3 years ago
Read 2 more answers
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