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mario62 [17]
3 years ago
9

An isosceles triangle has legs whose lengths are 10 inches and a base whose length is 12 inches. Which of

Mathematics
1 answer:
mezya [45]3 years ago
6 0

Answer:

48

Step-by-step explanation:

We have to find the height of the triangle to find its area. The altitude to the base of an isosceles triangle is also the median, meaning the altitude forms a 6-8-10 right triangle, so the length of the height is 8, and therefore the area is 0.5 * 8 * 12 = 48.

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Answer: 3sqrt(2)

Step-by-step explanation:

d = sqrt[(3-0)^2 + (4-1)^2]

d = sqrt[9+9]

d = sqrt(18) = 3sqrt(2)

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16. f(x) = x^3 + 3x^2-2 and f(- 1) = 0. If g(x)=f^-1* (x) the value of g^prime (0) is ( A) - 1/3 (B) - 1/4 (C ) -3 (D) nonexiste
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A firefighter sees a woman trapped in a building 47 feet up from the bottom floor. If the firefighter is parked 43 feet away fro
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48 degrees

Step-by-step explanation:

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What is the answer to, (4-1) . n = n . _
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Step-by-step explanation:

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Read 2 more answers
It is generally claimed that the average body temperature for healthy human adults is 98.6°F. To test this claim a simple random
Rzqust [24]

Answer:

Explained below.

Step-by-step explanation:

The information provided is as follows:

\mu=98.6^{o}F\\\bar x=98.1^{o}F\\s=0.9^{o}F\\n=9

(1)

A single mean test is to be performed in this case.

As the population standard deviation is not provided, a one-sample <em>t</em>-test will be used.

The correct option is b.

(2)

The null hypothesis is:

<em>H</em>₀: The average temperature in the population is 98.6°F, i.e. <em>μ </em>= 98.6°F.

The correct option is b.

(3)

The alternative hypothesis is:

<em>Hₐ</em>: The average temperature in the population is less than 98.6°F, i.e. <em>μ </em>< 98.6°F.

The correct option is c.

(4)

The standard deviation of the sample mean is as follows:

SD_{\bar x}=\frac{s}{\sqrt{n}}=\frac{0.9}{\sqrt{9}}=0.3^{o}F

Thus, the value of SD is 0.3°F.

(5)

Compute the value of test statistic as follows:

t=\frac{\bar x-\mu}{SD_{\bar x}}

  =\frac{98.1-98.6}{0.3}\\\\=-1.666666667\\\\\approx -1.67

Thus, the value of test statistic is -1.67.

(6)

The degrees of freedom of the test are:

df = n - 1

   = 9 - 1

   = 8

Thus, the degrees of freedom of the test is 8.

8 0
3 years ago
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