What is two numbers whose difference is 25.6
There are plenty of numbers and digits has a difference of
25.6. we shall illustrate these values using the following.
<span><span>1.
</span>50.0 – 24.4 = 25.6</span>
<span><span>2.
</span>100.1 – 74.5 = 25.6</span>
<span><span>
3.
</span>150 – 124.4 = 25.6</span>
<span><span>
4.
</span>78 – 52.4 = 25.6</span>
<span><span>
5.
</span>90 – 64.4 = 25.6</span>
<span><span>
6.
</span>88.5 -62.9 = 25.6</span>
Answer:
I am pretty sure that your answer would be 3.
Step-by-step explanation:
The reason why is because if B if half of line segment AD and AD is equal to 12, then B must be equal to 6 since half of 12 is 6. Next, since C is the mid-point for line segment BD then C must be 3 since half of 6 is 3. And finally, that means line segment BC is three since it is 1/2 of BD.
Hope this helps! :)
Answer:
aint no way :)))
Step-by-step explanation:
32 is the answer to the problem
Answer:
2.
A. (P+h)(x)
2x/x+4 (x-1) + x/x-1 (x+4)
2x^2-1/x^2-4
+
X^2+4/x^2-4
= 3x^2+3/x^2-4
B. (F-g)(x)
X^2-7x+6-x - 6
= x^2 -8x
C. (Fg)(x)
(X^2-7x+6)(x-6)
= x^3-13x^2+48x-36
D. (H/p)(x)
X/x-1 / 2x/x+4
X/x-1 / x+4/2x
= X^2+4x/2x^2-2x
3.
A. (F+g)(3)
X^2+1 + x-4
3^2+1 + 3-4
10 -1
= 9
B. (f-g)(0)
X^2+1 - x-4
0+1 -0-4
1-4
= -3
C. (Fg)(-k)
(X^2+1) (x-4)
(-k^2+1) (-k-4)
K^3+4k^2-k-4
D. (F/g)(k-2)
X^2+1 /x-4
K-2^2+1 / k-2 -2
= K^2-4k+5 / k-4
Step-by-step explanation:
