Hello!
Use the slope formula to solve for the slope of the line (m):
We can plug in the points (0, 4) and (1, 1) to solve:
Therefore, the slope of the line is -3.
To which graph does the point (8,-2) belong?
1 answer:
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The perimeter, by definition, is the outside measure of that figure. MN and LM are the same length and LK and NK are the same length....we just need to find the lengths! Use the distance formula to find the distance between the 2 points:
For the segment MN, use the coordinates of M as your x1, y1, and use the coordinates of N for x2, y2:
which simplifies to
which is 
So that is the length of both MN and LM. So far our perimeter is
Now let's use the same formula to find out the length of one of the longer segments:
which simplifies down to
which is of course
Since we have 2 of those lengths,
So our perimeter is, in the end,
That's the third choice down
For the segment MN, use the coordinates of M as your x1, y1, and use the coordinates of N for x2, y2:
which simplifies to
So that is the length of both MN and LM. So far our perimeter is
Now let's use the same formula to find out the length of one of the longer segments:
which simplifies down to
which is of course
Since we have 2 of those lengths,
So our perimeter is, in the end,
That's the third choice down
Answer:
all real numbers less than or equal to –3
Step-by-step explanation:
Look at the y-values that the graph shows. There are none greater than -3. Any value of -3 or less is possible.
Answer:
mid point of AB (0.5 , 0)
Step-by-step explanation:
2x + 5y = 1 2x = 1 - 5y
y = 2xy+ 5 = (1 - 5y)*y + 5 = y - 5y² + 5
y-y = y - 5y² + 5 - y = - 5y² + 5
0 = - 5y² + 5
5y² = 5
y² = 1
y = 1 or y = -1
if y = 1 x = 1/2 (1 - 5) = -2 .... point A (-2 , 1)
if y = -1 x = 1/2 (1 + 5) = 3 ..... point B (3 , -1)
mid point of AB (x' , y') : x' = 1/2 (x₁ + x₂) = 1/2 (-2 + 3) = 1/2
y' = 1/2 (y₁ + y₂) = 1/2 (-1 + 1) = 0
