The answer for the 1st bag is option B = 1/3
The answer for the 2nd bag is option C = 5/9
Number of marbles in 1st bag - 15 (6 red, 4 blue & 5 green)
Number of marbles in 2nd bag - 9 (3 red, 1 blue & 5 green)
The formula of probability = Total number of events in the outcome /total number of outcomes.
Now the probability that Aakesh will select a green marble from the 1st bag is 5(green marbles)/15(total number of marbles in 1st bag)
That is 5/15=1/3
Now the probability that Aakesh will select a green marble from the 2nd bag is 5(green marbles)/9(total number of marbles in 1st bag)
That is 5/9
To know more about probability go to - https://brainly.in/question/17157610?msp_poc_exp=6
Your answer is A.0.0684 dkg.
Hope this helps :)
If you need anymore help in future then let me know.
Mark Brainliest please
Answer:
<h2><em>
2ft by 2ft by 1 ft</em></h2>
Step-by-step explanation:
Total surface of the cardboard box is expressed as S = 2LW + 2WH + 2LH where L is the length of the box, W is the width and H is the height of the box. Since the cardboard box is without a lid, then the total surface area will be expressed as;
S = lw+2wh+2lh ... 1
Given the volume V = lwh = 4ft³ ... 2
From equation 2;
h = 4/lw
Substituting into r[equation 1;
S = lw + 2w(4/lw)+ 2l(4/lw)
S = lw+8/l+8/w
Differentiating the resulting equation with respect to w and l will give;
dS/dw = l + (-8w⁻²)
dS/dw = l - 8/w²
Similarly,
dS/dl = w + (-8l⁻²)
dS/dw = w - 8/l²
At turning point, ds/dw = 0 and ds/dl = 0
l - 8/w² = 0 and w - 8/l² = 0
l = 8/w² and w =8/l²
l = 8/(8/l² )²
l = 8/(64/I⁴)
l = 8*l⁴/64
l = l⁴/8
8l = l⁴
l³ = 8
l = ∛8
l = 2
Hence the length of the box is 2 feet
Substituting l = 2 into the function l = 8/w² to get the eidth w
2 = 8/w²
1 = 4/w²
w² = 4
w = 2 ft
width of the cardboard is 2 ft
Since Volume = lwh
4 = 2(2)h
4 = 4h
h = 1 ft
Height of the cardboard is 1 ft
<em>The dimensions of the box that requires the least amount of cardboard is 2ft by 2ft by 1 ft</em>
Answer:
In order to subtract fractions, there must be a common denominator (the number on the bottom of the fraction). 7 and 3 can be multiplied to get 21 (a common factor). To get each fraction to have a denominator of 21, they can be multiplied by 3 and 7 respectively and then subtracted. Attached is an image of the problem worked out. I apologize for the messy handwriting. Hope this helps!
Step-by-step explanation:
