Hope this helps! I have to type more words apparently for me to send this. Ok that should work!
William is 17 years old and Charmaine is 14 years old.
Step-by-step explanation:
Let x be the age of William and y be the age of Charmaine
Then
William is 3 years, older than Charmine.
x = y+3 Eqn 1
The sum of 3 times Charmaine's age and 2 times William's age is 76.
2x+3y = 76 Eqn 2
Putting x = y+3 in Eqn 2

Hence,
William is 17 years old and Charmaine is 14 years old.
Keywords: Linear equations, Variables
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I'm sorry I just really need the points
Answer:
69.08 m
Step-by-step explanation:
C = 2(pi) x r
Radius (r) = 11
Pi = 3.14
C = 2(3.14) x 11 = 69.08