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Anit [1.1K]
3 years ago
6

Ill give u brainliest pls help

Mathematics
2 answers:
Alenkinab [10]3 years ago
4 0

Answer:

It is answer A) 5x^8y^8z^3 (sq rt 2y)

Step-by-step explanation:

1. Factor out the perfect square

(sqr rt) 5^2 × 2x^16 × y^16 xyz^6

2. Split each factor to their own square root

3. Simplify these roots

cupoosta [38]3 years ago
3 0

Answer:

A

Step-by-step explanation:

First let's factor 50. This will look like this: 2*5*5. Since there are two 5s, together they form a perfect square so we can bring it out of the square root. This is what we have so far now: 5\sqrt{2x^{16} y^{17} z^{6} }. Now we should move on to x^{16}, since 16 is an even number, we can just divide it in half and put x to the power of 16/2 outside the square root. This is what we have so far: 5x^{8} \sqrt{2y^{17}z^{6}  }. Now let's work on y^{17}. Since 17 is an odd number, we will separate it like this: 16 + 1. Now we can divide 16 by 2 and put y to the power of 16 divided by 2 outside of the square root, but the last y^{1} will need to continue inside. So this is what we have so far: 5x^{8}y^{8}  \sqrt{2y z^{6}}. Now all we have to do is take care of the z^{6}. Since 6 is even we can just divide it by 2 and put the z to the power of 6 divided by 2 outside of the square root. This is what we have: 5x^{8}y^{8} z^{3}  \sqrt{2y}.

We are done!

I hope this made sense. Please give Brainliest!

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Please help, What is the nth term rule of the quadratic sequence below?<br> -4,1,12,29,52,81,116
Evgesh-ka [11]

Answer:

29-12 is a 17 difference

52-29 is a 23 difference (adding 6 to the number 17)

81-52 is a 29 difference (adding 6 to the number 23)

116-81 is a 35 difference (adding 6 to the number 29)

Step-by-step explanation:

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3 years ago
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2 years ago
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Shipping rates for Company A and Company B are shown in the tables below. Which company has shipping rates that you can represen
meriva

Company B; the ratios of cost to weight are equivalent.

Step-by-step explanation:

Step 1:

In the equation, y=kx k is the constant of proportionality.

If the values are in accordance with y=kx, the values of k will be constant for all the values.

So we determine the values of k for both the companies and see which has a constant k.

If y=kx, k = \frac{y}{x}. In these tables, y is the total cost and x is the weight in lbs.

Step 2:

For company A,

when y=10.55, x=1, k = \frac{10.55}{1} = 10.55,

when y=10.85, x=2, k = \frac{10.85}{2} = 5.425,

when y=11.15, x=3, k = \frac{11.15}{3} = 3.71666.

For company B,

when y=2.75, x=1, k = \frac2.75}{1} = 2.75,

when y=5.50, x=2, k = \frac{5.50}{2} = 2.75,

when y=8.25, x=3, k = \frac{8.25}{3} = 2.75.

So company B has a constant value of k=2.75.

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