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3 years ago

What is the probability that the two pointers will land on an odd number and letter C? Give the probability as a percent

Mathematics

2 answers:

Verizon [17]3 years ago

7 0

Answer:

Your answer would be 12.5%.

Step-by-step explanation:

There are two types of spinners here and the outcome of them is independent. That means

P(odd number, C) = P(odd number) * P(C)

There are two odd numbers out of four numbers in the first spinner. The chance of odd number will be:

P(odd) = 2/(2+2)= 1/2= 50%

There are four letters and the desired outcome is C. The chance for C will be:

P(C) = 1/4= 25%

Then the chance will be:

P(odd number, C) = P(odd number) * P(C)

P(odd number, C) =50% * 25% = 12.5%

Therefore, 12.5% will be your final answer.

Firlakuza [10]3 years ago

6 0

Answer:

12.5%

Step-by-step explanation:

hope this helps and its right

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If tan theta = 10/13 and cos theta > 0 then sin2theta is what ?

svetoff [14.1K]

$sin2\alpha = \frac{260}{269}$

Step-by-step explanation:

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Substituting values of P & B , $sin\alpha = \frac{10}{\sqrt{10^{2} + 13^{2}} } = \frac{10}{\sqrt{269} }$

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⇒ $sin2\alpha =$ $\frac{10}{\sqrt{269} }$ × $\sqrt{1 - (\frac{10}{\sqrt{269} })^{2} }$ ×2

⇒ $sin2\alpha = \frac{20}{\sqrt{269} }( \sqrt{\frac{269 - 100}{269} } )$

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3 years ago

Order these from least to greatest 3 39/40 , 3 19/20 , 3 1/2

Lera25 [3.4K]

Hey!

First change all the fractions so that they have a common denominator: 40

$3 \frac{39}{40} = 3 \frac{39}{40}$

$3 \frac{19 \times 2}{20 \times 2} = 3 \frac{38}{40}$

$3 \frac{1 \times 20}{2 \times 20} = 3 \frac{20}{40}$

Now order them:

$3 \frac{39}{40} , 3 \frac{19}{20} , 3 \frac{1}{2}$

Good luck and hope this helps! :)

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