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3 years ago

9

Please help me ASAP 100 PTS

2 answers:

Rom4ik [11]3 years ago

5 0

Answer:

The second choice

Step-by-step explanation:

Perimeter is calculated by adding the length and width but multiplied by 2. You add 3.2 and 1.5 and get 4.7. Multiply 4.7 by 2 would give you 9.4.

Area is multiplying the length and width. 3.2 multiplied by 1.5 would be 4.8

riadik2000 [5.3K]3 years ago

4 0

The answer is B.P=9.4 m, A 48m^2

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Please someone help me with the right answer help me find the area of this polygon

DanielleElmas [232]

Answer: The answer would be 1198.5 in.

Step-by-step explanation:

You would have to separate this polygon into 3 different shapes: a square, rectangle, and triangle. Here's a photo of the work:

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3 years ago

One zero of f(x)=x^3-2x^2-5x+6 is 1 what are other zeros of the function

elena-s [515]

Answer:

The other zeros are -2 and 3.

Step-by-step explanation:

As 1 is a zero then (x - 1) is a factor so we divide:

x - 1 )x^3-2x^2-5x+6(x^2-x-6

x^3-x^2

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4 years ago

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Question 6 of 10

ElenaW [278]

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This is the answer for apex!!!

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4 years ago

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Please help thank you!

Nadusha1986 [10]

Answer:

Step-by-step explanation:

lateral area formula= 2h(l+w) -------> 2(5) x 16+4

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3 years ago

Please help me with these calculus bc questions

zhannawk [14.2K]

4. Compute the derivative.

$y = 2x^2 - x - 1 \implies \dfrac{dy}{dx} = 4x - 1$

Find when the gradient is 7.

$4x - 1 = 7 \implies 4x = 8 \implies x = 2$

Evaluate $y$ at this point.

$y = 2\cdot2^2-2-1 = 5$

The point we want is then (2, 5).

5. The curve crosses the $x$ -axis when $y=0$ . We have

$y = \dfrac{x - 4}x = 1 - \dfrac4x = 0 \implies \dfrac4x = 1 \implies x = 4$

Compute the derivative.

$y = 1 - \dfrac4x \implies \dfrac{dy}{dx} = -\dfrac4{x^2}$

At the point we want, the gradient is

$\dfrac{dy}{dx}\bigg|_{x=4} = -\dfrac4{4^2} = \boxed{-\dfrac14}$

6. The curve crosses the $y$ -axis when $x=0$ . Compute the derivative.

$\dfrac{dy}{dx} = 3x^2 - 4x + 5$

When $x=0$ , the gradient is

$\dfrac{dy}{dx}\bigg|_{x=0} = 3\cdot0^2 - 4\cdot0 + 5 = \boxed{5}$

7. Set $y=5$ and solve for $x$ . The curve and line meet when

$5 = 2x^2 + 7x - 4 \implies 2x^2 + 7x - 9 = (x - 1)(2x+9) = 0 \implies x=1 \text{ or } x = -\dfrac92$

Compute the derivative (for the curve) and evaluate it at these $x$ values.

$\dfrac{dy}{dx} = 4x + 7$

$\dfrac{dy}{dx}\bigg|_{x=1} = 4\cdot1+7 = \boxed{11}$

$\dfrac{dy}{dx}\bigg|_{x=-9/2} = 4\cdot\left(-\dfrac92\right)+7=\boxed{-11}$

8. Compute the derivative.

$y = ax^2 + bx \implies \dfrac{dy}{dx} = 2ax + b$

The gradient is 8 when $x=2$ , so

$2a\cdot2 + b = 8 \implies 4a + b = 8$

and the gradient is -10 when $x=-1$ , so

$2a\cdot(-1) + b = -10 \implies -2a + b = -10$

Solve for $a$ and $b$ . Eliminating $b$ , we have

$(4a + b) - (-2a + b) = 8 - (-10) \implies 6a = 18 \implies \boxed{a=3}$

so that

$4\cdot3+b = 8 \implies 12 + b = 8 \implies \boxed{b = -4}$ .

5 0

2 years ago