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3 years ago

Please help me ASAP 100 PTS

Mathematics

2 answers:

Rom4ik [11]3 years ago

5 0

Answer:

The second choice

Step-by-step explanation:

Perimeter is calculated by adding the length and width but multiplied by 2. You add 3.2 and 1.5 and get 4.7. Multiply 4.7 by 2 would give you 9.4.

Area is multiplying the length and width. 3.2 multiplied by 1.5 would be 4.8

riadik2000 [5.3K]3 years ago

4 0

The answer is B.P=9.4 m, A 48m^2

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stiv31 [10]

(4/10)(5/100)=20/1000

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3 years ago

Suppose Casey Title Company normally charges $300 for services related to selling a house. As part of a summer special, Casey of

g100num [7]

Given :

Casey's company charges , C = $300.

In summer special, Casey offers customers a trade discount of 25%.

To Find :

Charges during summer.

Solution :

Let, x is the amount of charges they take during summer.

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3 years ago

Let f(x,y,z) = ztan-1(y2) i + z3ln(x2 + 1) j + z k. find the flux of f across the part of the paraboloid x2 + y2 + z = 3 that li

Sophie [7]

Consider the closed region $V$ bounded simultaneously by the paraboloid and plane, jointly denoted $S$ . By the divergence theorem,

$\displaystyle\iint_S\mathbf f(x,y,z)\cdot\mathrm dS=\iiint_V\nabla\cdot\mathbf f(x,y,z)\,\mathrm dV$

And since we have

$\nabla\cdot\mathbf f(x,y,z)=1$

the volume integral will be much easier to compute. Converting to cylindrical coordinates, we have

$\displaystyle\iiint_V\nabla\cdot\mathbf f(x,y,z)\,\mathrm dV=\iiint_V\mathrm dV$
$=\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=1}\int_{z=2}^{z=3-r^2}r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta$
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Then the integral over the paraboloid would be the difference of the integral over the total surface and the integral over the disk. Denoting the disk by $D$ , we have

$\displaystyle\iint_{S-D}\mathbf f\cdot\mathrm dS=\frac\pi2-\iint_D\mathbf f\cdot\mathrm dS$

Parameterize $D$ by

$\mathbf s(u,v)=u\cos v\,\mathbf i+u\sin v\,\mathbf j+2\,\mathbf k$
$\implies\mathbf s_u\times\mathbf s_v=u\,\mathbf k$

which would give a unit normal vector of $\mathbf k$ . However, the divergence theorem requires that the closed surface $S$ be oriented with outward-pointing normal vectors, which means we should instead use $\mathbf s_v\times\mathbf s_u=-u\,\mathbf k$ .

Now,

$\displaystyle\iint_D\mathbf f\cdot\mathrm dS=\int_{u=0}^{u=1}\int_{v=0}^{v=2\pi}\mathbf f(x(u,v),y(u,v),z(u,v))\cdot(-u\,\mathbf k)\,\mathrm dv\,\mathrm du$
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$\displaystyle\iint_{S-D}\mathbf f\cdot\mathrm dS=\frac\pi2-(-2\pi)=\dfrac{5\pi}2$

6 0

3 years ago

What is the vertex of y=(x-2)-7

Zina [86]

Answer:

The vertex of this equation is (2, -7)

Step-by-step explanation:

In order to find the vertex of this equation we start with the base form of the vertex form.

y = a(x - h) + k

With this equation (h, k) is the vertex. You can see that 2 lines up with h and -7 lines up with k. This shows that (2, -7) is the vertex.

7 0

3 years ago