QP=24 cm
RS=11.25 cm
QS=18.75 cm
<u>Explanation</u>:
Given that TQ bisects <RTP
(1)
consider ΔRQS and ΔRPT
QS||PT,RP and RT are transversals
(alternate angles)(2)
comparing (1) and (2)
and triangle SQT is isocelus
Therefore SQ=ST(sides opposite to equal angles in an isocelus triangle)
Therefore <RQS=<RPT(corresponding angles)
<RSQ=<RTP(corresponding angles)
therefore by AA criterion for similarity
ΔRQS~ΔRPT
According to the property of similar triangles


Answer:
1 and 1/3
Step-by-step explanation:
3a² -4a +1 = 0
3a²- 3a - a+ 1= 0
3a(a-1) - (a-1)= 0
(a-1)(3a -1)= 0
a-1= 0 ⇒ a= 1
3a - 1= 0 ⇒ 3a= 1 ⇒ a= 1/3
Answer:
C. The mean is 111.9F and the median is 114.5F.
Step-by-step explanation:
The mean is 111.9 given that (105 + 113 + 122 + 121 + 116 + 118 + 107 + 93)/8 = 111.875 which can be rounded to 111.9 F.
Organizing the values we have:
[93, 105, 107, 113, 116, 118, 121, 122]
We find that the median is going to be between 113 and 116. Therefore:
(113 + 116) / 2 = 114,5
Therefore, the correct answer is option C.
G has 2 local minimums, you can tell because there are 2 dips in the line before it goes of to infinity.
Both questions have the same answer so the answer to both would be
Local Min: (-2,-3), (3,0)