Answer:
x = 2 csc(1) y - π/4
Step-by-step explanation:
Solve for x:
y = 1/2 sin(1) (x + π/4)
y = 1/2 (x + π/4) sin(1) is equivalent to 1/2 (x + π/4) sin(1) = y:
1/2 sin(1) (x + π/4) = y
Divide both sides by sin(1)/2:
x + π/4 = 2 csc(1) y
Subtract π/4 from both sides:
Answer: x = 2 csc(1) y - π/4
Let the width be w, then the length is 2w - 2.5.
Perimeter = 2(length + width)
40.6 = 2(2w - 2.5 + w) = 2(3w - 2.5)
3w - 2.5 = 40.6/2 = 20.3
3w = 20.3 + 2.5 = 22.8
w = 22.8/3 = 7.6
Therefore, width is 7.6 cm.
Answer: the answers are below
Step-by-step explanation:
1 meal = 2/3 of a can of wet dog food, 1/8 of a bag of dry dog food, and 3/5 a patty of special meat
Food for 1 day: 2 meals = 2(2/3) = 4/3 of a can of wet dog food, 2(1/8) = 1/4 of a bag of dry dog food, and 2(3/5) = 6/5 a patty of special meat
The trainer goes to the store and buys 24 cans of wet food, 4 bags of dry food and 3 packages of meat (3*6 = 18 patties)
He has:
there is wet food for: 24/(4/3) = 24*3/4 = 18 days
there is dry food for: 4/(1/4) = 4*4 = 16 days
there is special meat food for: 18/(6/5) = 18*5/6 = 15 days
since the minimum for 15, 16 and 18 is 15 the dog will have food for 15 days and first he will run out of special meat.
Calculate the z-score for the given data points in the item using the equation,
z-score = (x - μ) / σ
where x is the data point, μ is the mean, and σ is the standard deviation.
Substituting,
(47.7) z-score = (47.7 - 52.5)/2.4 = -2
This translates to a percentile of 2.28%.
(54.9) z-score = (54.9 - 52.5)/2.4 = 1
This translates to a percentile of 84.13%.
Then, subtract the calculate percentiles to give us the final answer of <em>81.85%.</em>
Thus, 81.85% of the Siberian Husky sled dogs are expected to weigh between 47.7 and 54.9 lbs.
If the probability of even is 1/4 that is a quarter. A quarter of 120 is 120/4= 30 times
