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nataly862011 [7]
2 years ago
6

Please tell me the answers i am confused and need help

Mathematics
1 answer:
joja [24]2 years ago
8 0

Answer:

Simplified= 7x+6 When x=3 the expression=27

Step-by-step explanation:

You might be interested in
Decide if the following statement is valid or invalid. If two sides of a triangle are congruent then the triangle is isosceles.
Naya [18.7K]

Answer:

Step-by-step explanation:

Properties of an Isosceles Triangle

(Most of this can be found in Chapter 1 of B&B.)

Definition: A triangle is isosceles if two if its sides are equal.

We want to prove the following properties of isosceles triangles.

Theorem: Let ABC be an isosceles triangle with AB = AC.  Let M denote the midpoint of BC (i.e., M is the point on BC for which MB = MC).  Then

a)      Triangle ABM is congruent to triangle ACM.

b)      Angle ABC = Angle ACB (base angles are equal)

c)      Angle AMB = Angle AMC = right angle.

d)      Angle BAM = angle CAM

Corollary: Consequently, from these facts and the definitions:

Ray AM is the angle bisector of angle BAC.

Line AM is the altitude of triangle ABC through A.

Line AM is the perpendicular bisector of B

Segment AM is the median of triangle ABC through A.

Proof #1 of Theorem (after B&B)

Let the angle bisector of BAC intersect segment BC at point D.  

Since ray AD is the angle bisector, angle BAD = angle CAD.  

The segment AD = AD = itself.

Also, AB = AC since the triangle is isosceles.

Thus, triangle BAD is congruent to CAD by SAS (side-angle-side).

This means that triangle BAD = triangle CAD, and corresponding sides and angles are equal, namely:

DB = DC,

angle ABD = angle ACD,

angle ADB = angle ADC.

(Proof of a).  Since DB = DC, this means D = M by definition of the midpoint.  Thus triangle ABM = triangle ACM.

(Proof of b) Since angle ABD = angle ABC (same angle) and also angle ACD = angle ACB, this implies angle ABC = angle ACB.

(Proof of c) From congruence of triangles, angle AMB = angle AMC.  But by addition of angles, angle AMB + angle AMC = straight angle = 180 degrees.  Thus 2 angle AMB = straight angle and angle AMB = right angle.

(Proof of d) Since D = M, the congruence angle BAM = angle CAM follows from the definition of D.  (These are also corresponding angles in congruent triangles ABM and ACM.)

QED*

*Note:  There is one point of this proof that needs a more careful “protractor axiom”.  When we constructed the angle bisector of BAC, we assumed that this ray intersects segment BC.  This can’t be quite deduced from the B&B form of the axioms.  One of the axioms needs a little strengthening.

The other statements are immediate consequence of these relations and the definitions of angle bisector, altitude, perpendicular bisector, and median.  (Look them up!)

Definition:  We will call the special line AM the line of symmetry of the isosceles triangle.  Thus we can construct AM as the line through A and the midpoint, or the angle bisector, or altitude or perpendicular bisector of BC. Shortly we will give a general definition of line of symmetry that applies to many kinds of figure.

Proof #2 (This is a slick use of SAS, not presented Monday.  We may discuss in class Wednesday.)

The hypothesis of the theorem is that AB = AC.  Also, AC = AB (!) and angle BAC = angle CAB (same angle).  Thus triangle BAC is congruent to triangle BAC by SAS.

The corresponding angles and sides are equal, so the base angle ABC = angle ACB.

Let M be the midpoint of BC.  By definition of midpoint, MB = MC. Also the equality of base angles gives angle ABM = angle ABC = angle ACB = angle ACM.  Since we already are given BA = CA, this means that triangle ABM = triangle ACM by SAS.

From these congruent triangles then we conclude as before:

Angle BAM = angle CAM (so ray AM is the bisector of angle BAC)

Angle AMB = angle AMC = right angle (so line MA is the perpendicular bisector of  BC and also the altitude of ABC through A)

QED

Faulty Proof #3.  Can you find the hole in this proof?)

In triangle ABC, AB = AC.  Let M be the midpoint and MA be the perpendicular bisector of BC.

Then angle BMA = angle CMA = right angle, since MA is perpendicular bisector.  

MB = MC by definition of midpoint. (M is midpoint since MA is perpendicular bisector.)

AM = AM (self).

So triangle AMB = triangle AMC by SAS.

Then the other equal angles ABC = ACB and angle BAM = angle CAM follow from corresponding parts of congruent triangles.  And the rest is as before.

QED??

8 0
2 years ago
A basketball game is 45 minutes long. 20 minutes have already been played. write an equation that represents how many minutes m
snow_lady [41]
<h2 /><h2>45 - 20 = m</h2><h2 /><h2>OR m = 45 - 20</h2><h2 /><h2>Hope that helps!</h2>
4 0
2 years ago
Read 2 more answers
What is the value of the expression. -8-(-3) <br> = -8 blank 3 <br> = blank
Mashutka [201]

Answer:

Step-by-step explanation:

-(-)=+

so  -8-(-3)=-8+3

=-5

6 0
3 years ago
Point D with coordinates (3,-5) is reflected across the x-axis, then translated by the vector ⟨−4,6⟩ . Where is its image locate
Dmitriy789 [7]

Answer:

A. quadrant l

4 0
3 years ago
Read 2 more answers
Natalie is going mountain biking. She can buy a bike for $250 or she can rent a bike for $30 an hour. In both cases, she must al
scZoUnD [109]

Given :

Natalie is going mountain biking. She can buy a bike for $250 or she can rent a bike for $30 an hour.

In both cases, she must also rent a helmet for $5 an hour.

To Find :

Which inequality shows the number of hours Natalie must bike for the cost of buying a bike to be less than renting a bike.

Solution :

Let, after t hours total money required is ( if she rent bike ).

T = 30t.

Money required to purchase bike , M = $250.

For cost of buying a bike to be less than renting a bike :

30t>250\\\\t > \dfrac{25}{3}\ hours\\\\t>8\dfrac{1}{3}\ hours\\\\t>8\ hours \ 20 \ minutes

Hence, this is the required solution.

5 0
3 years ago
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