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kiruha [24]
3 years ago
7

Simplify the expression 3^7/3^5

Mathematics
1 answer:
Setler79 [48]3 years ago
3 0

Answer:

9

Step-by-step explanation:

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Novay_Z [31]
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➷ Use this formula:

Area of circle = \pi r^{2}

However, as we are using 3.14 for 'pi', we can write it like this:

Area = (3.14)r^{2}

'r' is the radius which is 12ft

Substitute this value into the equation:

Area = (3.14)12^{2}

Solve:

Area = 452.16

Multiply this value by 0.75 to get the answer:

452.16 x 0.75 = 339.12

339.12 square feet is being watered

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5 0
3 years ago
Help me on problem 9 please and I will thank you
Tomtit [17]
A: minutes
16a > (with a line under it) 136

The awnser would be 8 minutes and 50 seconds. 136 ÷ 16 = 8.5
a > (with a line under it) 8.5

I hope I helped! :D
5 0
3 years ago
Read 2 more answers
At Sunrise Donuts you can buy 6 donuts and 2 kolaches for $8.84. One kolache and 4 donuts would cost $5.36. What is the price of
Lelechka [254]
Set up a system of equations like this, where "k" represents a kolache and "d" represents a donut:

\left \{ {{6d +2k = 8.84} \atop {k+4d = 5.36}} \right.

We're solving for d.  First, we can rearrange the second equation to have it equal k:

k + 4d = 5.36
k = 5.36 - 4d

Next, we can substitute this in for k in the first equation:

6d + 2k = 8.84
6d + 2(5.36 - 4d) = 8.84
6d + 10.72 - 8d = 8.84

Finally, we can get the value of d if we solve this equation:

-2d + 10.72 = 8.84
-2d= -1.88
d = 0.94

You can buy a donut at Sunrise Donuts for $0.94.
3 0
3 years ago
Can someone please help me with number 15
Stells [14]
The first thing you have to do is order them least to greatest. Once that is done you need to find your first, second and third quartile. to find them is simple. You have to find the median of the data set. Then from the number on either side of the median you have to find the median of this data sets. The median of the entire set is your second quartile then the medium to the left is your first and the median to your right is the third quartile. For the number line you need to make numbers that are appropriate for the number range. Then place your least number, the first, second, and third quartile, then place your greatest number. then draw a line up from the median and the first and third quartile and create a box. 
8 0
3 years ago
<img src="https://tex.z-dn.net/?f=y%20%3D%203%20%2B%20%5Csqrt%5B3%5D%7B16%20-%208%7D%20" id="TexFormula1" title="y = 3 + \sqrt[3
Korvikt [17]

3 +  \sqrt[3]{16 - 8}
= 3 +  \sqrt[3]{8}  \\  = 3 + 2 \\  = 5


8 0
3 years ago
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