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3 years ago

Graph f(x)= -2x + 4. What is x when f(x) is -8?

Mathematics

2 answers:

yuradex [85]3 years ago

5 0

- 8 = - 2x + 4
2x = 12
x = 6

PSYCHO15rus [73]3 years ago

3 0

You only need to know two points to draw a line. So, just calculate any two points by assuming x to be any number.

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3(a+b)=a+2 make a subject of the formula

Anit [1.1K]

Answer:

a = 2 - 3b

Step-by-step explanation:

3(a + b) = a + 2 expand

3a + 3b = a + 2

3a - a = 2 - 3b

2a = 2 - 3b

a = 2 - 3b

7 0

3 years ago

a model of a railroad station has has a scale of 1 inch equals 3.5 ft the dimensions of the model railroad station are 34 inches

andrew11 [14]

I would say that it would be 119ft by 63ft

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3 years ago

Quadratic Equation

Natasha_Volkova [10]

Step-by-step explanation:

The sum of ages of two friends is 13 years.

The product of their ages is 42.

Let the age of 1st friend and 2nd friend is x, y respectively.

1 st condition= The sum of ages of two friends is 13 yrs.

i.e x+y = 13........ (I)

2nd condition= The product of their ages is 42.

i.e X*y = 42........(ii)

From equation (I)

X+y = 13

or, X = 13-y........ (iii)

Putting the equation (iii) in equation (ii).

X*y= 42

(13-y) * y = 42

13y - y^2 = 42

${y}^{2} - 13y + 42 = 0$

${y}^{2} - (7 + 6)y + 42= 0$

${y}^{2} - 7y - 6y + 42 = 0$

$y(y - 7) - 6(y - 7) = 0$

$(y - 6) (y - 7) = 0$

Either; y-6 = 0

y = 6

Or;

y-7=0

y = 7

Keeping the value of y as "7" in equation (ii)

x*y = 42

7x = 42

X = 42/7

Therefore, the value of X is 6.

Therefore, either 1st friend is 6 years and 2nd is 7 years.

Hope it helps...

7 0

3 years ago

The weight of a mandarin orange is about 6 ounces. A basket that weighs 4 ounces will hold m mandarin oranges, the total weight

trasher [3.6K]

Answer:

4 + 6m = 70

Step-by-step explanation:

4 is the basket

6m is the total weight of mandarins

70 is total weight

7 0

3 years ago

If the probability of selecting, without replacement, 2 red marbles from a bag containing only red and blue marbles is 3 55 and

Marat540 [252]

Answer:

Step-by-step explanation:

Let T = the TOTAL number of marbles in the bag.

We are told that 3 of those marbles are red

P(select a red marble first) = 3/T

Once we've removed the first red marble, there are T-1 marbles remaining and 2 of them are red

So, P(select a red marble second) = 2/(T-1)

Okay, now let's use probability rules to answer the question....

P(select 2 red marbles) = P(select a red marble first AND select a red marble second)

= P(select a red marble first) x P(select a red marble second)

= 3/T x 2/(T-1)

= 6/(T² - T)

We're told that P(select 2 red marbles) = 3/55

So, we can write: 6/(T² - T) = 3/55

Cross multiply to get: 3(T² - T) = (6)(55)

Divide both sides by 3 to get: T² - T = (2)(55)

Evaluate: T² - T = 110

Rearrange: T² - T - 110 = 0

Factor: (T - 11)(T + 10) = 0

So, EITHER T = 11 OR T = -10

Since T cannot be negative, it must be the case that T = 11

6 0

2 years ago