Answer:
Adjacent = 9.75 inches.
Step-by-step explanation:
Given the following data;
Hypothenus = 12 inches
Opposite = 7 inches
To find the other leg i.e adjacent, we would use Pythagorean' theorem given by the formula;
Hypothenus² = opposite² + adjacent²
Substituting into the formula, we have;
12² = 7² + adjacent²
144 = 49 + adjacent²
Adjacent² = 144 - 49
Adjacent² = 95
Taking the square root of both sides, we have;
Adjacent = 9.75 inches.
Therefore, the other leg is 9.75 inches.
If SU bisects TSV, then TSU = USV
4y + 11 = 6y + 5
6y - 4y = 11 - 5 = 6
y = 6/2 = 3
Therefore, m<TSU = 4(3) + 11 = 12 + 11 = 23
First you need the formula for SA of a cylinder: SA = 2(πr^2) + 2πr*h
(area of the top and bottom circles plus the side)
Then plug your values into the equation and rearrange to make h the subject:
1470.3 = 2π13^2 + 2π*13*h
26πh = 1470.3 - 338π
h = (1470.3 - 338π)/26π
=5.00042...
so h is approximately 5 units :)
Answer:
There will be $5624.32 in the account after 3 years if the interest is compounded annually.
There will be $5630.812 in the account after 3 years if the interest is compounded semi-annually.
There will be $5634.125 in the account after 3 years if the interest is compounded quarterly.
There will be $5636.359 in the account after 3 years if the interest is compounded monthly
Step-by-step explanation:
Tamira invests $5,000 in an account
Rate of interest = 4%
Time = 3 years
Case 1:
Principal = 5000
Rate of interest = 4%
Time = 3 years
No. of compounds per year = 1
Formula :

A=5624.32
There will be $5624.32 in the account after 3 years if the interest is compounded annually.
Case 2:
Principal = 5000
Rate of interest = 4%
Time = 3 years
No. of compounds per year = 2
Formula : 

A=5630.812
There will be $5630.812 in the account after 3 years if the interest is compounded semi-annually.
Case 3:
Principal = 5000
Rate of interest = 4%
Time = 3 years
No. of compounds per year = 4
Formula : 

A=5634.125
There will be $5634.125 in the account after 3 years if the interest is compounded quarterly.
Case 4:
Principal = 5000
Rate of interest = 4%
Time = 3 years
No. of compounds per year = 4
Formula :

A=5636.359
There will be $5636.359 in the account after 3 years if the interest is compounded monthly