Solve the equation 6x^2 + 15x + 3= 2x^2 to the nearest tenth.

Mathematics

1 answer:

Slav-nsk [51]3 years ago

5 0

Answer:

x = -0.2 and x = -3.5

Step-by-step explanation:

Combine like terms in the given equation, by subtracting 2x^2 from both sides:

6x^2 + 15x + 3 = 2x^2

-2x^2 = -2x^2

----------------------------------

4x^2 + 15x + 3 = 0

This is a quadratic equation. We'll find the two solutions using the quadratic equation

-b ± √(b^2 - 4ac)

x = ---------------------------

Here the coefficients of the quadratic are a = 4, b = 15 and c = 3.

Thus, the discriminant b^2 - 4ac is 15^2 - 4(4)(3), or +177

and from that we know we'll find two real, unequal roots.

-15 ± √177

The roots are: x = ------------------- , or x = -0.2 and x = -3.5

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