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k0ka [10]
3 years ago
6

MARKING BRAINLIEST TO FIRST PERSON WHO IS CORRECT! I need help with #13

Mathematics
1 answer:
levacccp [35]3 years ago
4 0

Answer:

True

False

False

Step-by-step explanation:

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Solve all of the above
Alisiya [41]

Answer:

no ones gonna solve that for 5 points

Step-by-step explanation:

sorry

6 0
3 years ago
How do you find the surface area of this shape?
geniusboy [140]
I got 595 for surface area
You multiply each side like an individual shape.
6 0
4 years ago
Write the standard form of the equation of each line.<br><br> 1. y= -2/5x+1<br> 2. y+3 = -3/2(x+1)
gavmur [86]

Answer:

1. 2x + 5y = 5

2. 3x + 2y = -9

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Futhe Mathematics<br><img src="https://tex.z-dn.net/?f=%28Cos%20%7B%7D%5E%7B4%7Dt%20-Sin%20%7B%7D%5E%7B4%7Dt%20%29%20%20%5Cdiv%2
Nastasia [14]

Answer:

cos2t/cos²t

Step-by-step explanation:

Here the given trigonometric expression to us is ,

\longrightarrow \dfrac{cos^4t - sin^4t }{cos^2t }

We can write the numerator as ,

\longrightarrow \dfrac{ (cos^2t)^2-(sin^2t)^2}{cos^2t }

Recall the identity ,

\longrightarrow (a-b)(a+b)=a^2-b^2

Using this we have ,

\longrightarrow \dfrac{(cos^2t + sin^2t)(cos^2t-sin^2t)}{cos^2t}

Again , as we know that ,

\longrightarrow sin^2\phi + cos^2\phi = 1

Therefore we can rewrite it as ,

\longrightarrow \dfrac{1(cos^2t - sin^2t)}{cos^2t}

Again using the first identity mentioned above ,

\longrightarrow \underline{\underline{\dfrac{(cost + sint )(cost - sint)}{cos^2t}}}

Or else we can also write it using ,

\longrightarrow cos2\phi = cos^2\phi - sin^2\phi

Therefore ,

\longrightarrow \underline{\underline{\dfrac{cos2t}{cos^2t}}}

And we are done !

\rule{200}{4}

Additional info :-

<em>D</em><em>e</em><em>r</em><em>i</em><em>v</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>o</em><em>f</em><em> </em><em>c</em><em>o</em><em>s</em><em>²</em><em>x</em><em> </em><em>-</em><em> </em><em>s</em><em>i</em><em>n</em><em>²</em><em>x</em><em> </em><em>=</em><em> </em><em>c</em><em>o</em><em>s</em><em>2</em><em>x</em><em> </em><em>:</em><em>-</em>

We can rewrite cos 2x as ,

\longrightarrow cos(x + x )

As we know that ,

\longrightarrow cos(y + z )= cosy.cosz -  siny.sinz

So that ,

\longrightarrow cos(x+x) = cos(x).cos(x) - sin(x)sin(x)

On simplifying,

\longrightarrow cos(x+x) = cos^2x - sin^2x

Hence,

\longrightarrow\underline{\underline{cos (2x) = cos^2x - sin^2x }}

\rule{200}{4}

7 0
3 years ago
Subtract.
bija089 [108]
5x²-(-2x²) = 7x²
(-3x)-(-x) = (-3x+x)=-2x
(-2)-(10)=-12
7x²-2x-12

3 0
3 years ago
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