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stira [4]
3 years ago
15

Triangle ACB is the pre-image and triangle DFE is the image. What is the scale factor of the dilation?

Mathematics
1 answer:
Reika [66]3 years ago
7 0

Answer:

½

Step-by-step explanation:

the scale factor of dilation = 6/12 = ½

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Unknown variables in Equations <br><br> 1. 7=w/14<br> 2.42/n=7<br> 3. 324/18=a
belka [17]

Answer:

w = 98

n = 6

a = 18

Step-by-step explanation:

Question 1)

7 = w/ 14

All you need to do is multiply each side by 14 to find w:

7(14) = W

W = 98

Question 2)

42/n = 7

For this one, first multiply each side by "n":

42 = 7n

and then divide both sides by 7:

N = 6

Question 3)

All you need to do for this question is divide 324 by 18 to find "a":

324/18 = a

a = 18

I hope this helps!

-TheBusinessMan

4 0
3 years ago
If 2&gt; -a, then a &lt; -2.<br> True<br> False
Nonamiya [84]

Answer:

False

Step-by-step explanation:

Flip the equation.

−a<2

Divide both sides by -1.

a>−2

4 0
3 years ago
What is 4 3/8 - 2 2/3
docker41 [41]
6/3 + 2/3 = (6 + 2)/3:
4 + 3/8 - (6 + 2)/3

6 + 2 = 8:
4 + 3/8 - 8/3

Put 4 + 3/8 - 8/3 over the common denominator 24. 4 + 3/8 - 8/3 = (24×4)/24 + (3×3)/24 + (8 (-8))/24:
(24×4)/24 + (3×3)/24 + (8 (-8))/24

24×4 = 96:
96/24 + (3×3)/24 + (8 (-8))/24

3×3 = 9:
96/24 + 9/24 + (8 (-8))/24

8 (-8) = -64:
96/24 + 9/24 + (-64)/24

96/24 + 9/24 - 64/24 = (96 + 9 - 64)/24:
(96 + 9 - 64)/24

 | 1 | 
 | 9 | 6
+ | | 9
1 | 0 | 5:
(105 - 64)/24


 | 0 | 10 | 
 | 1 | 0 | 5
- | | 6 | 4

 | 0 | 4 | 1:
Answer:  41/24 or decimal 1.70833333.....
7 0
3 years ago
For each of the following vector fields
olga nikolaevna [1]

(A)

\dfrac{\partial f}{\partial x}=-16x+2y

\implies f(x,y)=-8x^2+2xy+g(y)

\implies\dfrac{\partial f}{\partial y}=2x+\dfrac{\mathrm dg}{\mathrm dy}=2x+10y

\implies\dfrac{\mathrm dg}{\mathrm dy}=10y

\implies g(y)=5y^2+C

\implies f(x,y)=\boxed{-8x^2+2xy+5y^2+C}

(B)

\dfrac{\partial f}{\partial x}=-8y

\implies f(x,y)=-8xy+g(y)

\implies\dfrac{\partial f}{\partial y}=-8x+\dfrac{\mathrm dg}{\mathrm dy}=-7x

\implies \dfrac{\mathrm dg}{\mathrm dy}=x

But we assume g(y) is a function of y alone, so there is not potential function here.

(C)

\dfrac{\partial f}{\partial x}=-8\sin y

\implies f(x,y)=-8x\sin y+g(x,y)

\implies\dfrac{\partial f}{\partial y}=-8x\cos y+\dfrac{\mathrm dg}{\mathrm dy}=4y-8x\cos y

\implies\dfrac{\mathrm dg}{\mathrm dy}=4y

\implies g(y)=2y^2+C

\implies f(x,y)=\boxed{-8x\sin y+2y^2+C}

For (A) and (C), we have f(0,0)=0, which makes C=0 for both.

4 0
3 years ago
Homework, pls help ( 10 points )
NeTakaya
4(8x + 3y)

= 32x + 12y
4 0
3 years ago
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