All categories

3 years ago

Each Christmas elf makes x toys in an hour. n elves work for t hours to produce 1000 toys.

Mathematics

2 answers:

inn [45]3 years ago

8 0

Answer:

Khan has it (x)(n)(t)=1000 thanks

Step-by-step explanation:

k0ka [10]3 years ago

5 0

Answer:

e(X x T)=1000

Step-by-step explanation:

You do the number of toys they make(X) times the hours they work(T). Then multiply all of it by the number of elves(e). All of that equals the 1000 toys they make all together.

You might be interested in

What is the formula for the following geometric sequence? -5, -10, -20, -40, ... an = -5 · 2n - 1 an = -5 · (-2)n - 1 an = -2 ·

vazorg [7]

$-5 * 2^{n-1}$

8 0

3 years ago

a bag contains 10 white gold balls and 6 striped golf balls. a golfer wants to add 112 golf balls to the bag. he wants the ratio

wolverine [178]

Answer:70 white golf balls and 42 striped golf balls

Step-by-step explanation:

First we find the ratio of white to striped balls

White golf balls = 10

Striped golf balls = 6

Ratio = 10/6 = 5/3

We are told a golfer wants to add extra 112 balls to the already 16 balls

And the ratio after adding 112 balls must stay the same

First we label the extra golf balls to be added x and y

x = white golf balls

y = striped golf balls

So since we know the 112 balls added is a combination of the extra white golf balls and striped golf balls, we create an equation for that, labelling it (1)

x + y = 112 (1)

And we are told that after putting these extra balls the ratio must remain the same, which is 5/3

which will be (10 white balls + x) divided by (6 striped ball + y) will be equals to 5/3

So we create another equation for this, labelling it (2)

(10+x)/(6+y) = 5/3 (2)

So we have two simultaneous equations

We pick (1)

x + y = 112

We either make x or y the subject of formula, I choose to make x the subject of formula, we label the equation (3)

take y to the other side, causing it to change to -y

x = 112 - y (3)

We then work with (2)

(10+x)/(6+y) = 5/3

We cross multiply

3(10+x) = 5(6+y)

We open the brackets

Making the equation simplified and labelling it (4)

30 +3x = 30 + 5y

Collect like terms

3x -5y = 30-30

3x -5y = 0 (4)

Remember from (3) we know that

x = 112 -y

So we put (3) in (4)

3(112 - y) - 5y = 0

Open bracket

336 -3y -5y =0

336 -8y = 0

Transfer -8y to the other side, changing to +8y

336 = 8y

Divide both sides by 8

336/8 = y

42 = y

y = 42

from (3) we know that x equals 112 - y

So we put y = 42 in (3)

x = 112 - y

x = 112 -42 = 70

x = 70

So therefore number of white golfs balls and striped golfs balls to be added to keep the same ratio is 70 and 42 respectively

4 0

3 years ago

The following list gives the number of pets for each of 13 students.

podryga [215]

The mode's of this set of data are 1,2, and 4.

6 0

3 years ago

There are 2,000 eligible voters in a precinct. A total of 500 voters are randomly selected and asked whether they plan to vote f

Ann [662]

Answer:

$0.7 - 2.58 \sqrt{\frac{0.7(1-0.7)}{500}}=0.647$

$0.7 + 2.58 \sqrt{\frac{0.7(1-0.7)}{500}}=0.753$

And the 99% confidence interval would be given (0.647;0.753).

So the correct answer would be:

a. 0.647 and 0.753

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Solution to the problem

The estimated population proportion for this case is:

$\hat p = \frac{350}{500}=0.7$

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 99% confidence interval the value of $\alpha=1-0.99=0.01$ and $\alpha/2=0.005$ , with that value we can find the quantile required for the interval in the normal standard distribution.