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3 years ago

What is 3/4 divided by 1/8? Consider drawing a model or using the common denominator method to help you solve the problem.

Mathematics

1 answer:

Kazeer [188]3 years ago

3 0

3/32 if this is right can you please make me the brainiest answer thanks

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A sugar solution was made by mixing 7 ml of a 50% sugar solution and 3 ml of a 80% sugar solution. Find the concentration of the

pochemuha

7 * 0.5 + 3 * 0.8 = 3.5 + 2.4 = 5.9

<span>5.9/10 X 100 = 59%

</span><span>59% concentration of new mixture</span>

4 0

3 years ago

At what point do the lines y= 2x + 3 and y = 5x - 9 intersect?

QveST [7]

Answer:

(4,11)

Step-by-step explanation:

y=2x+3

y=5x-9

the first equation is equal to the second equation so

2x+3=5x-9

put like terms together

2x-5x= -9-3

-3x= -12

divide both sides by -3

.•.x=4

now, use the value of x to find the value of y like this:

y=2x+3 (x=4)

y=2(4)+3

y=8+3

y=11

therefore, the two lines intersect at the point (4,11)

4 0

3 years ago

Help ASAP! use the second image attached to answer!

xenn [34]

Answer:

only the circle graph

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

For number 6, evaluate the definite integral.

maks197457 [2]

$\bf \displaystyle \int\limits_{0}^{28}\ \cfrac{1}{\sqrt[3]{(8+2x)^2}}\cdot dx\impliedby \textit{now, let's do some substitution}\\\\
-------------------------------\\\\
u=8+2x\implies \cfrac{du}{dx}=2\implies \cfrac{du}{2}=dx\\\\
-------------------------------\\\\$

$\bf \displaystyle \int\limits_{0}^{28}\ \cfrac{1}{\sqrt[3]{u^2}}\cdot \cfrac{du}{2}\implies \cfrac{1}{2}\int\limits_{0}^{28}\ u^{-\frac{2}{3}}\cdot du\impliedby 
\begin{array}{llll}
\textit{now let's change the bounds}\\
\textit{by using } u(x)
\end{array}\\\\
-------------------------------\\\\
u(0)=8+2(0)\implies u(0)=8
\\\\\\
u(28)=8+2(28)\implies u(28)=64$

$\bf \\\\
-------------------------------\\\\
\displaystyle \cfrac{1}{2}\int\limits_{8}^{64}\ u^{-\frac{2}{3}}\cdot du\implies \cfrac{1}{2}\cdot \cfrac{u^{\frac{1}{3}}}{\frac{1}{3}}\implies \left. \cfrac{3\sqrt[3]{u}}{2} \right]_8^{64}
\\\\\\
\left[ \cfrac{3\sqrt[3]{(2^2)^3}}{2} \right]-\left[ \cfrac{3\sqrt[3]{2^3}}{2} \right]\implies \cfrac{12}{2}-\cfrac{6}{2}\implies 6-3\implies 3$

3 0

3 years ago

A team of 9 tennis players can order bags with their uniforms

jeka94

Answer:

Step-by-step explanation:

5 0

3 years ago