<h3><u>Answer;</u></h3>
357 mg/mL
<h3><u>Explanation;</u></h3>
- Solubility is defined to be the maximum amount of solute that will dissolve in a given amount of solvent at a specific temperature. The solubility of a salt is one of many physical properties that depend on temperature.
- At room temperature 25 °C, the solubility of salt or Sodium Chloride is 357 mg/mL.
- For many solutes, increasing the temperature increases the solubility of the solute. The solubility of sodium chloride or table salt is only slightly affected by temperature increase.
The amount of water that will be produced is 50.36 grams
<h3>Stoichiometric problems</h3>
The metabolism of glucose is represented by the following equation:
The mole ratio of glucose metabolized to the water produced is 1:6.
Mole of 84.0 g glucose = 84/180.156 = 0.4662 moles
Equivalent mole of water = 0.4662 x 6 = 2.7975 moles
Mass of 2.7975 moles water = 2.7975 x 18 = 50.36 grams
More on stoichiometric problems can be found here: brainly.com/question/14465605
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Answer:
there will a definite decrease in solute solution
Explanation:
acid reaction acting upon negative charge.
Answer:
P2≈393.609Kpa so I think the answer is 394 kPa
Explanation:
PV=mRT Ideal Gas Law
m and R are constant because they dont change for the problem. That means
PV/T=mR = constant
so P1*V1/T1=P2*V2/T2 and note that the temperatures are in absolute temperatures (Kelvin) because you can't divide by zero.
So P2 = P1*V1*T2/(V2*T1) = 101325 Pa * 700 mL * 303K/(200 mL*273K)
P2 = 393609 Pa
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I got this from google, hope it helps! :)
