Answer:
E = 2.93×10⁻¹⁹ J
Explanation:
Given data:
Wavelength of photon = 678 nm (678×10⁻⁹ m)
Energy of photon = ?
Solution:
Formula:
E = h c/λ
h = 6.63×10⁻³⁴ Js
c = 3×10⁸ m/s
E = 6.63×10⁻³⁴ Js × 3×10⁸ m/s / 678×10⁻⁹ m
E = 19.89 ×10⁻²⁶ Jm / 678×10⁻⁹ m
E = 0.0293×10⁻¹⁷ J
E = 2.93×10⁻¹⁹ J
We have to first find the number of moles of Freon-12 in the sample using the ideal gas law equation
PV = nRT
n =

since the number of moles at both conditions given and at stp we can write the following formula

where parameters for the given conditions are on the left side and parameters for STP conditions are on the right side of the equation
where P1 - pressure - 252.5 kPa
V1 - volume - 28.42 x 10⁻³ m³
R - universal gas constant
T1 - 331 K
STP conditions
P2 - 101 325 Pa
T2 - 273 K
substituting these values in the equation

V = 58.41 L
Volume at STP is 58.41 L
Fossil fuel combustion increases the acidity of rain because the sulfur dioxide is produced.
Because of fuel combustion, sulfur dioxide goes up into the atmosphere as the hot gases rise, than it reacts with water and oxygen in the air and form sulfuric <span>acid:
</span>Balanced chemical reaction: SO₂(g) + 2O₂(g) + 2H₂O → 2H₂SO₄.
The surface area expressed in square feet of a single face of a pile is 1.45 square feet.
<u>Explanation:</u>
The dimensions of the pillar are given as 14 in
14 in
(1 feet = 12 inch)
According to the pillar dimensions mentioned in the problem, the length of the pillar should be 15 inches, height by 14 inches and the width by 14 inches.
There will be two surface areas of the concrete pile, one implies side surface area and the other is end surface area.
For calculating the side surface area,
Area of the side surface = 14 in
15 in
=
= 1.16
1.25
= 1.45 square feet.
(In the given question, only a single face is asked so there is no need to find the surface area of the end face.)
Bohr suggested, that there are definitive shells of particular energy and angular momentum in which an electron can revolve. It was not in Rutherford's model