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aleksandr82 [10.1K]
3 years ago
5

A line passes through the point (4,9) and has a slope of 5/2.

Mathematics
1 answer:
kkurt [141]3 years ago
8 0

Answer:

5/2

Step-by-step explanation:

BRAINLIEST

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Simply.... plz someone give me the answer
ch4aika [34]

Answer:

Y= 9xi/4 - 9i - 11

X= 4yi/9 - 4 + 44i/9

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3 years ago
Solve the inequality. Write the solution in set-builder notation.
Salsk061 [2.6K]
-4x - 17 ≥ -41
<u>       +17   +17</u>
        <u>-4x</u> ≥ <u>-24</u>
         -4       -4
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8 0
3 years ago
Suppose you have developed a scale that indicates the brightness of sunlight. Each category in the table is 4 times brighter tha
raketka [301]

According to the developed scale, a radiant day is <u>16 times</u> brighter than a dim day.

We assume the brightness of a dim day to be x.

According to the developed scale, the brightness of an illuminated day will be 4 times that of a dim day.

Thus, the brightness of an illuminated day = 4*the brightness of a dim day = 4x.

According to the developed scale, the brightness of a radiant day will be 4 times that of an illuminated day.

Thus, the brightness of a radiant day = 4*the brightness of an illuminated day = 4*4x = 16x.

Now, the ratio of the brightness of a radiant day to the brightness of a dim day = 16x:x = 16x/x = 16:1.

Thus, according to the developed scale, a radiant day is <u>16 times</u> brighter than a dim day.

Learn more about the developed scale at

brainly.com/question/4970963

#SPJ1

The question provided is incomplete. The complete question is:

"Suppose you have developed a scale that indicates the brightness of sunlight. Each category in the table is 4 times brighter than the next lower category. For example, a day that is dazzling is 4 times brighter than a day that is radiant. How many times brighter is a radiant day than a dim day?

Dim=2

Illuminated=3

Radiant=4

Dazzling=5"

8 0
1 year ago
Please solve Questions - 18 , 20 , 21 <br>Show proper work. Thank-you!
Ymorist [56]
18. If f(x)=[xsin πx] {where [x] denotes greatest integer function}, then f(x) is:
since x denotes the greatest integers which could the negative or the positive values, also x has a domain of all real numbers, and has no discontinuous point, then x is continuous in (-1,0).

Answer: B]

20. Given that g(x)=1/(x^2+x-1) and f(x)=1/(x-3), then to evaluate the discontinuous point in g(f(x)) we consider the denominator of g(x) and f(x). g(x) has no discontinuous point while f(x) is continuous at all points but x=3. Hence we shall say that g(f(x)) will also be discontinuous at x=3. Hence the answer is:
C] 3

21. Given that f(x)=[tan² x] where [.] is greatest integer function, from this we can see that tan x is continuous at all points apart from the point 180x+90, where x=0,1,2,3....
This implies that since some points are not continuous, then the limit does not exist.
Answer is:
A]


3 0
3 years ago
What is the annual wage for a person who works 2,000 hours and earns $12.00 an hour?
daser333 [38]
$24,000 per year!! Hope it helps :) goodluck
3 0
2 years ago
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