A line passes through the point (4,9) and has a slope of 5/2.
1 answer:
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Answer:
B
Step-by-step explanation:
x² - 12x + 11 = 0 ( subtract 11 from both sides )
x² - 12x = - 11
To complete the square
add ( half the coefficient of the x- term )² to both sides
x² + 2(- 6)x + 36 = - 11 + 36
(x - 6)² = 25 ( take square root of both sides )
x - 6 = ± = ± 5 ( add 6 to both sides )
x = 6 ± 5
Then
x = 6 - 5 = 1 ⇒ (1, 0 )
x = 6 + 5 = 11 ⇒ (11, 0 )
4x - y + 3 =0 is the equation of the line
Step-by-step explanation:
Given:
The slope of the line = 5
The points through with the line passes = (0,3)
To Find:
The equation of the line =?
Solution:
The equation y = mx + b
where m is the slope and (0,b) is the y-intercept.
The slope is given which is m = 4 and a point (0,3)
Then you can use slope-point equation
where is the given point
y - (3) = 4(x - 0)
y - 3 = 4(x)
y = 4x - 22
y - 3 = 4x
4x - y + 3 = 0