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abruzzese [7]
3 years ago
8

Proportional relationships

Mathematics
1 answer:
Assoli18 [71]3 years ago
7 0

1. 720 words in 18 minutes

2. The number 240 is missing

3. A. 120

I hope this helps you

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4 years ago
Urgent! Math help! Answer?
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3 years ago
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For this problem, it is described that a set of number (x, y, z, ...) is calculated by a series of identical operation using the preceding number. In this problem if we let x as the first number, the second number y is, y = (x/2) + 6. Then the 3rd number z is equal to, z = (y/2) + 6, so on. Thus for this problem, the solution is <span>D: 100, 56, 34, 23 through trial and error.</span>
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