The binary fission , is the asexual reproduction which is found in prokaryotes. In binary fission a cell divide into two daughter cell. Amoeba is the best example of binary fission in which gentic material is divide and via mitotic division further cell is divide into to daughter cell . So we conclude that, the result of binary fission is formation of daughter cell.
Metaphase I believe that is the answer to your question
I think the answer should be medulla oblongata or foramen magnum.
The major nerves that leave brain should form a thick cord in the brain stem that called medulla oblongata. Medulla oblongata will pass a big hole in the base of the skull that called foramen magnum. Depends on what part the question asked(bone or tissue), it probably between those two options.
Answer:
- GLYCOLYSIS :- Glycolysis is the metabolic pathway that converts glucose C₆H₁₂O₆, into pyruvic acid, CH₃COCOOH. The free energy released in this process is used to form the high-energy molecules adenosine triphosphate and reduced nicotinamide adenine dinucleotide
- PRODUCTS :- Glycolysis produces 2 ATP, 2 NADH, and 2 pyruvate molecules: Glycolysis, or the aerobic catabolic breakdown of glucose, produces energy in the form of ATP, NADH, and pyruvate, which itself enters the citric acid cycle to produce more energy.
- INPUT:- Glycolysis is the first step in cellular respiration, occurring in all living cells. Overall, the input for glycolysis is one glucose, two ATP and two NAD+ molecules giving rise to two pyruvate molecules, four ATP and two NADH.
- BREAKDOWN:- During glycolysis, glucose ultimately breaks down into pyruvate and energy; a total of 2 ATP is derived in the process (Glucose + 2 NAD+ + 2 ADP + 2 Pi --> 2 Pyruvate + 2 NADH + 2 H+ + 2 ATP + 2 H2O). The hydroxyl groups allow for phosphorylation. The specific form of glucose used in glycolysis is glucose 6-phosphate
- STAGES:-
- Reaction 1: glucose phosphorylation to glucose 6-phosphate.
- Reaction 2: isomerization of glucose 6-phosphate to fructose 6-phosphate
- Reaction 3: phosphorylation of fructose 6-phosphate to fructose 1,6-bisphosphate
- Reaction 4: cleavage of fructose 1,6-bisphosphate into two three-carbon fragments.
Explanation:
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Answer:
step 1: mRNA attaches to the ribosome
step 2: tRNA's attach to free amino acids in the cytoplasmic "pool" of amino acids
step 3: tRNA carries its specific amino acid to the ribosome
step 4: tRNA "delivers" its amino acid based on complementary pairing of a triplet code (anticodon) with the triplet code (codon) of the mRNA
step 5: Enzyme "hooks" the amino acid to the last one in the chain forming a peptide bond
step 6: Protein chain continues to grow as each tRNA brings in its amino acid and adds it to the chain