All categories

2 years ago

Is y=6/x-2 linear or nonlinear

Mathematics

2 answers:

zhannawk [14.2K]2 years ago

8 0

Answer:

Non linear. It is a curve not a line.

Vikki [24]2 years ago

4 0

No liner
Reason? Because 8 is a negative number

You might be interested in

What is x +92 x 32 when x is 50

ANEK [815]

The answer is 184 like du

4 0

3 years ago

Read 2 more answers

Find all the zeroes of the equation(with simple steps).

uysha [10]

Answer-

The zeros are, $5,\ -5,\ 4i,\ -4i$

Solution-

$\Rightarrow -3x^4+27x^2+1200=0$

$\Rightarrow -3(x^2)^2+27(x^2)+1200=0$

Here,

a = -3, b = 27, c = 1200

So,

$x^2=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}$

$=\dfrac{-27\pm \sqrt{-27^2-4\cdot (-3)\cdot 1200}}{2\cdot (-3)}$

$=\dfrac{-27\pm \sqrt{729+14400}}{-6}$

$=\dfrac{-27\pm 123}{-6}$

$=\dfrac{-27+123}{-6},\ \dfrac{-27- 123}{-6}$

$=\dfrac{96}{-6},\ \dfrac{-150}{-6}$

$=-16,\ 25$

So,

$\Rightarrow x^2=25,\ -16$

$\Rightarrow x=\sqrt{25},\ \sqrt{-16}$

$\Rightarrow x=5,\ -5,\ 4i,\ -4i$

8 0

2 years ago

What is the x coordinate of the intersection of y=4x-10 and y=(x-2) to the power of 2 +2

aleksley [76]

Answer:

Step-by-step explanation:

Equating the y-values gives an equation in x.

4x -10 = (x -2)^2 +2

0 = x^2 -4x +4 +2 -4x +10 . . . . . . . . eliminate parentheses, subtract 4x-10

x^2 -8x +16 = 0

(x -4)^2 = 0

x = 4

The x-coordinate of the one point of intersection is x = 4.

6 0

3 years ago

Help pls which ones are the answer

Degger [83]

Answer:

Step-by-step explanation:

if t is the total acreage and its reduced by 8%, then t -0.08

3 0

3 years ago

Please add am explanation.

iren2701 [21]

Answer:

5(k + 1) and 5k + 5

Step-by-step explanation:

The easiest way to do this is to pick any number to substitute in for the variable k for ALL of the expressions, and find the expressions that equal the same as the first expression being compared.

For example, lets just make k equal 1 to make things easy. Plug 1 into k into the first expression. 2k + 2 + k + 3 + 2k → 2(1) + 2 + (1) + 3 + 2(1) = 10.

Now we do the same to the rest of the expressions and see which ones ALSO equal 10.

5(k + 1) → 5(1 + 1) = 10

5k + 5 → 5(1) + 5 = 10

5 + k^5 → 5 + (1)^5 = 6

5k^5 → 5(1)^5 = 5

5 0

2 years ago