Answer:
Hopefully 6-7
Step-by-step explanation:
if you spending that much on pizza yo hi as better stay home and deleivered it
If I understand what you are asking, you can use the median as an average since it is not affected by the mean ( median is a measure of center). Since a mean is affected by outliers, it might lower the score if there are very low outliers. But note that if there are outliers way <em>greater </em>it can increase the average. You can use the Inter Quartile Range if shown on a box plot ( measure of variability).
Answer:
4:10.
Step-by-step explanation:
4:10 would be one.
Solution:
1) Distribute
12a+12b
Done!
Answer:
![(x^\frac{3}{8})^\frac{3}{4} = \sqrt[32]{x^9}](https://tex.z-dn.net/?f=%28x%5E%5Cfrac%7B3%7D%7B8%7D%29%5E%5Cfrac%7B3%7D%7B4%7D%20%20%3D%20%5Csqrt%5B32%5D%7Bx%5E9%7D)
Step-by-step explanation:
Given

Required
Convert to radical form

Evaluate the exponents


Split the exponent

Apply the following law of indices
![(x^a)^\frac{1}{b} = \sqrt[b]{x^a}](https://tex.z-dn.net/?f=%28x%5Ea%29%5E%5Cfrac%7B1%7D%7Bb%7D%20%3D%20%5Csqrt%5Bb%5D%7Bx%5Ea%7D)
So, we have:
![(x^\frac{3}{8})^\frac{3}{4} = \sqrt[32]{x^9}](https://tex.z-dn.net/?f=%28x%5E%5Cfrac%7B3%7D%7B8%7D%29%5E%5Cfrac%7B3%7D%7B4%7D%20%20%3D%20%5Csqrt%5B32%5D%7Bx%5E9%7D)