Answer:
Credit recovery is a term used to describe a wide variety of educational strategies and programs that give high school students who have failed a class the opportunity to redo coursework or retake a course through alternate means—and thereby avoid failure and earn academic credit.
Step-by-step explanation:
I'm not sure if this help but if it does good luck with it.
Answer:
you have selected the correct option for the first part
in the second part, the answer is "there is no solution"
in the third part, the answer is "one solution" which is (0 , 1)
brainly it if you found this helpful
<span>The number of workers must be increased by 28%.</span>
You can use the quadratic formula:
X = (-b +/- ✓b^2 - 4ac)/2a
You then can get:
X = 2 or 1.5
Hope this helps! :)
Answer:
The amount of metal recovered at the eight pass is approximately 4.27 kg
Step-by-step explanation:
The mass of metal recovered formed the following geometric sequence;
32 kg, 24 kg, 18 kg, 13.5 kg
∴ The first term, a = 32 kg
The common ratio in the geometric sequence is found as follows;
r = a·r/a = 24 kg/(32 kg) = 0.75
r = a·r²/a·r = 18 kg/(24 kg) = 0.75
r = a·r³/a·r² = 13.5 kg/(18 kg) = 0.75
The mass of the metal recovered in the eight pass will be the 8th term of the geometric series given as follows;
nth term = a·rⁿ⁻¹
a = 32, r = 0.75, n = 8
∴ 8th term = 32·(0.75)⁸⁻¹ = 32·0.75⁷ = 2187/512 ≈ 4.27
The amount of metal recovered at the eight pass ≈ 4.27 kg.
