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Monica [59]
3 years ago
12

A force is applied to a 12 kg box. The force is applied parallel to the motion of the box. Determine the force acting on the box

if it moves 22 meters and increases the box’s speed from 10 m/s to 25 m/s.
Physics
1 answer:
antiseptic1488 [7]3 years ago
8 0

Answer:

Force = 143.16 Newton

Explanation:

Given the following data;

Distance, S = 22 m

Initial velocity, U = 10 m/s

Final velocity, V = 25 m/s

Mass = 12 kg

To find the force acting on the box;

First of all, we would determine the acceleration of the box using the third equation of motion;

V² = U² + 2aS

25² = 10² + 2*a*22

625 = 100 + 44a

625 - 100 = 44a

525 = 44a

Acceleration, a = 525/44

Acceleration, a = 11.93 m/s²

Next, we find the force;

Force = mass * acceleration

Force = 12 * 11.93

Force = 143.16 Newton

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Explanation:

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3 years ago
5. What is the force of gravity on a
zvonat [6]

Answer:

32.40 N

Explanation:

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W = mg

W = (20 kg) (1.62 m/s²)

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3 0
4 years ago
An electric scooter has a battery capable of supplying 150 Wh of energy. If friction forces and other losses account for 60.0% o
german

Answer:

First, we need to convert Wh to joules. This can be easily done. Wh means that you are doing 1W of work per hour. We need to find out how much work this is.

We lost 60% of this energy on friction and other losses which means that this leaves us with:

We are going to use this energy to do work against the force of gravity. This means that when we reach our maximum height all of our energy will be used and thus converted the potential energy in the gravitational field.

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5 0
3 years ago
A police car is driving north with a siren making a frequency of 1038 hz. Moops is driving north behind the police car at 12 m/s
Marianna [84]

Answer:

The police car is moving at 41.24 m/s.

Explanation:

To find the speed of the police car we need to use the Doppler equation:

f = f_{0}(\frac{v + v_{r}}{v + v_{s}})      

Where:

v: is the speed of the sound = 343 m/s

v_{r}: is the speed of the receiver = 12 m/s

v_{s}: is the speed of the source =?

f: is the observed frequency = 959 Hz

f₀: is the emitted frequency = 1038 Hz          

Both terms are positive in the fraction because the velocity of the sound is in the opposite direction to both velocities of the police car and the other car.  

By solving the above equation for v_{s} we have:        

v_{s} = \frac{f_{0}(v + v_{r})}{f} - v = \frac{1038(343 + 12)}{959} - 343 = 41.24 m/s  

Therefore, the police car is moving at 41.24 m/s.

I hope it helps you!                  

8 0
3 years ago
The Chair o
Anvisha [2.4K]

Lol they’re not gonna be able to answer if they can’t watch the video

5 0
3 years ago
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