Question

In a hydroelectric dam, water falls 33.0 m and then spins a turbine to generate electricity. What is

Answer 1

Answer:

$m = 1.74 \times 10^5 kg/s$

Explanation:

As we know that potential energy is given as

$U = mgh$

here we know that

m = 1 kg

h = 33 m

now we have

$U = 1(9.8)(33)$

$U = 323.4 J$

Part b)

Now we need total power given as

$P = 45 MW$

so we have

$P = \frac{\Delta U}{t}$

here we know that it is 80% efficient so we can write

$P = 0.80(\frac{\Delta U}{\Delta t})$

$45 \times 10^6 = 0.80(m)(323.4)$

$m = 1.74 \times 10^5 kg/s$