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nekit [7.7K]
2 years ago
6

Where are you most likely to build up enough static charge to receive a

Physics
2 answers:
FromTheMoon [43]2 years ago
6 0

You're most likely to build up enough static charge to receive a  shock by walking around in a carpeted restaurant in the desert. (A)

Walking on carpet is the fastest way to accumulate charge, and the dry desert air prevents the charge from dribbling off of you and away.

When I walked on stones in the Sinai Desert, the dry wind with a little bit of sand or dust in it built up enough static charge on me that I got a shock every time I stood less than a foot away from my partner.

I had the same experience a few years later near Ouarzazate in the interior of Morocco.

When you hear people say "the desert is dry", they mean it's <em>DRY !  </em>

gulaghasi [49]2 years ago
4 0

Answer:

A. In a carpeted resteraunt in the desert

Explanation:

i like anime

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Which of these would not contribute to a global increase in temperature?
Katyanochek1 [597]

Answer:

planting trees - increasing the amount of animal life on earth

Explanation:

from all the other options given, all except planting trees will increase global temperature.

1. deforestation: this removes vegetative cover and the amount of oxygen in the atmosphere.

2. increasing the use of gasoline burning vehicles: burning gasoline produces carbon dioxide which is a green house gas which traps heat in the atmosphere and causes global warming

3. increasing the industrial release of carbon dioxide: carbon dioxide is released when gasoline is burned in industries, this in-turn causes global warming.

Trees produces oxygen and sucks in carbon dioxide which causes global warming. more trees mean more oxygen and less carbon dioxide which translates to less global increase in temperature

6 0
3 years ago
Theweight ofof body is 420N .Calculate its mass​
Nady [450]

Answer:

42.87

Explanation:

Google

<u>OR</u>

<u></u>

420/9.8 which equals 42.87.

6 0
3 years ago
(this is a question from my leap practice)
ki77a [65]
The answer is C. in sort of a way. You can't technically see black matter. However, it is holding the galaxies together.
4 0
3 years ago
Earth has a mass of 5,970,000 how would scientists express this in a number scientific notation
Kazeer [188]

Taking into account the definition of Scientific notation, the correct representation of 5,970,000 in scientific notation is 5.97×10⁶.

<h3>Definition of scientific notation</h3>

Scientific notation is a quick way to represent a number using powers of base 10.

The numbers are written as a product:

a×10ⁿ

where:

  • a is a real number greater than or equal to 1 and less than 10, to which a decimal point is added after the first digit if it is a non-integer number.
  • n is a whole number, which is called an exponent or an order of magnitude. Represents the number of times the point decimal is shifted. It is always an integer, positive if it is shifted to the left, negative if it is shifted to the right.

<h3>This case</h3>

In this case, to write the number 5,970,000 in scientific notation, the following steps are performed:

  • The decimal point is moved to the left as many spaces until it reaches the right of the first digit. This number will be the value of a in the previous expression. Then a = 5.97
  • The base 10 is written with the exponent equal to the number of spaces that the decimal point moves. This is a positive number because the decimal point is shifted to the left, and it will have a value of n = 6.

Finally, the correct representation of 5,970,000 in scientific notation is 5.97×10⁶.

Learn more about scientific notation:

brainly.com/question/18073768


#SPJ1

4 0
1 year ago
A merry-go-round with a a radius of R = 1.9 m and moment of inertia I = 209 kg-m2 is spinning with an initial angular speed of ω
RideAnS [48]

Answer:

340.67 kgm²/s

Explanation:

R = Radius of merry-go-round = 1.9 m

I = Moment of inertia = 209 kgm²

\omega_i = Initial angular velocity = 1.63 rad/s

m = Mass of person = 73 kg

v = Velocity = 4.8 m/s

Initial angular momentum is given by

L=I\omega_i\\\Rightarrow L=209\times 1.63\\\Rightarrow L=340.67\ kgm^2/s

The initial angular momentum of the merry-go-round is 340.67 kgm²/s

8 0
3 years ago
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