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Art [367]
3 years ago
8

What is the equation of the line x-3y = 18 in slope-intercept form drag and drop the appropriate number,symbol, or variable to e

ach box.

Mathematics
1 answer:
Jobisdone [24]3 years ago
6 0
Simple...

you have: x-3y=18

You want to convert it into slope-intercept form or y=mx+b form-->>>

x-3y=18

Isolate the variable-->>

x-3y=18
-x      -x

-3y=-x+18

Now simply divide...



y=
You might be interested in
Can someone please help me extra points
Maslowich

Answer:

4) m: 1.25   b: 6         Equation: y= 1.25x + 6

5) m: 20      b: 10     Equation: y= 40x + 10

6) m: -2       b: 0       Equation: y= -2x + 0

7) m: 1/5      b: 1       Equation: y= 1/5x + 1

8) -8.7 = 1.3x + 0

I really hope this helps!

3 0
3 years ago
12. At noon the temperature was 30 degrees Celsius. At night it becomes 25 degrees Celsius. How
yawa3891 [41]

Answer:

5 degrees colder

Step-by-step explanation:

You take the starting point then subract the ending point and you get your answer. But in order to know if its colder or warmer is to know that the higher the number, the hotter, and the lower the number, the colder.

6 0
3 years ago
Read 2 more answers
A sculpture of a clothespin is 20 feet high. A normal clothespin of this shape is five inches high. Using this scale, how many f
kodGreya [7K]
This is the concept of scale factor. The linear scale factor is given by:
(height of sculpture)/(height of clothespin)
=20/(5/12)
=48
Given that a woman is 5ft 7 in, the sculpture of this woman would be:
height of sculpture=(scale factor)*(height of the woman)
height of the woman=5 ft 7 inches=5 7/12 ft=67/12 ft
hence the height of the sculpture will be:
67/12×48
=268 ft

Answer: 268 ft

7 0
3 years ago
Read 2 more answers
What is the slope of (1,5) and (4,-2)
andriy [413]

Answer:-2-5÷4-1=-1

Step-by-step explanation:

6 0
3 years ago
Suppose you are investigating the relationship between two variables, traffic flow and expected lead content, where traffic flow
prisoha [69]

Answer:

The answers is " Option B".

Step-by-step explanation:

CI=\hat{Y}\pm t_{Critical}\times S_{e}

Where,

\hat{Y}= predicted value of lead content when traffic flow is 15.

\to df=n-1=8-1=7

 95\% \ CI\  is\  (463.5, 596.3) \\\\\hat{Y}=\frac{(463.5+596.3)}{2}\\\\

     =\frac{1059.8}{2}\\\\=529.9

Calculating thet-critical valuet_{ \{\frac{\alpha}{2},\ df \}}=-2.365

The lower predicted value =529.9-2.365(Se)

463.5=529.9-2.365(Se)\\\\529.9-463.5=2.365(Se)\\\\66.4=2.365(Se)\\\\Se=\frac{66.4}{2.365} \\\\Se=28.076

When 99\% of CI use as the expected lead content: \to 529.9\pm t_{0.005,7}\times 28.076 \\\\=(529.9 \pm 3.499 \times 28.076)\\\\=(529.9 \pm 98.238)\\\\=(529.9-98.238, 529.9+98.238)\\\\=(431.662, 628.138)\\\\=(431.6, 628.1)

8 0
3 years ago
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