Answer and Step-by-step explanation:
we have the following data:
Point estimate = sample mean = \ bar x = 12.39
Population standard deviation = \ sigma = 3.7
Sample size = n = 177
a) the margin of error with a 90% confidence interval
α = 1 - 90%
alpha = 1 - 0.90 = 0.10
alpha / 2 = 0.05
Z \ alpha / 2 = Z0.05 = 1,645
Margin of error = E = Z \ alpha / 2 * (\ sigma / \ sqrtn)
we replace:
E = 1.645 * (3.7 / \ sqrt177)
Outcome:
E = 0.46
b) margin of error with a 99% confidence interval
α = 1-99%
alpha = 1 - 0.99 = 0.01
alpha / 2 = 0.005
Z \ alpha / 2 = Z0.005 = 2,576
Margin of error = E = Z \ alpha / 2 * (\ sigma / \ sqrtn)
we replace:
E = 2,576 * (3.7 / \ sqrt177)
Outcome:
E = 0.72
c) A larger confidence interval value will increase the margin of error.
Yes
Explanation:
2x9=18 and 1+8=9
The pattern repeats
First you add 3+6, then take 9 and multiply by 2 which is 18, the do 26-18 which is 8×3=24.
12×3=36-12=24.
So 24=24
Your answer is A.
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Step-by-step explanation: wejfuncuwebfucwbrpubfwuefb38248237r8
Answer:
Confidence interval: (0.04649,0.04913)
Step-by-step explanation:
We are given the following in the question:
Sample size, n = 100,000
Number of people who donated, x = 4781
95% Confidence interval:
Putting the values, we get:
is the required 95% confidence interval for the true proportion of their entire mailing list who may donate.
