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Lostsunrise [7]
2 years ago
6

If ANQZ - ACBK, find BK. *O BK = 39O BK = 16O BK = 65O BK = 27​

Mathematics
1 answer:
patriot [66]2 years ago
5 0

9514 1404 393

Answer:

  (c)  BK = 65

Step-by-step explanation:

Corresponding sides are proportional in similar triangles, so ...

  ZT/ZQ = KF/KB

  27/(2x +7) = 45/(4x+1)

  27(4x+1) = 45(2x +7) . . . cross-multiply

  3(4x +1) = 5(2x +7) . . . . divide by 9

  12x +3 = 10x +35 . . . . . eliminate parentheses

  2x = 32 . . . . . . . . . . . . . subtract 10x+3

  x = 16 . . . . . divide by 2

Then the length of BK is ...

  BK = 4x+1 = 4·16 +1

  BK = 65

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find the y value for the point that splits segment GH in half of point G is located at (-3,5) and point H is located at (0,-2)
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Michael jogs at 3 miles per hour and Jack runs at 4.5 miles per hour. If Michael starts at 2:00 pm and Jack starts on the same c
tresset_1 [31]

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It will take Jack 40 minutes to cover the same distance which Micheal covers in 60 minutes. Both will meet at 3 miles distance at 3 pm.

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Micheal  runs 3 miles in one hour or 60 minutes.

In one minute he runs 3/60= 1/20  or 0.05miles.

Jack runs 4.5 miles in one hour or 60 minutes.

In one minute he runs 4.5/60= 45/600= 9/120= 3/40  or 0.075 miles.

So Jack is 0.075/0.05 = 1.5 times faster than Micheal.

or Micheal is 1.5 times slower than Jack.

Jack starts from 2:20 pm and at 3 pm he will run 0.075(40 minutes)= 3miles

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3 0
3 years ago
Area triangles? it says show work so pls do
coldgirl [10]

\large{\underline{\underline{\pmb{\sf {\color {blue}{Solution:}}}}}}

Given,

Area = 225 yd²

Base = 30 yd

Height = [To be calculated]

To find:

The height of the given triangle.

We know that, area of a triangle is:

\frac{1}{2}  \times (b \times h) \\  \\  \leadsto \frac{1}{2} \times (30 \times h) \\  \\  \leadsto \frac{1}{2}   \times 30h \\  \\  \leadsto  \frac{1}{ \cancel{2}} \times  \cancel{30}h \\  \\  \leadsto1 \times 15h \\  \\  \leadsto \: h = 15 \: yd

Therefore, the require height is 15 yd.

\green\starProof:

\frac{1}{2}  \times (b \times h) \\  \\  \leadsto \frac{1}{2}  \times (30 \times 15) \\  \\  \leadsto \frac{1}{ \cancel{2}}   \times  \cancel{450} \\  \\  \leadsto1 \times 225  \\  \\  area = 225  {yd}^{2}

\boxed{ \frak \red{brainlysamurai}}

6 0
1 year ago
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