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Lostsunrise [7]
2 years ago
6

If ANQZ - ACBK, find BK. *O BK = 39O BK = 16O BK = 65O BK = 27​

Mathematics
1 answer:
patriot [66]2 years ago
5 0

9514 1404 393

Answer:

  (c)  BK = 65

Step-by-step explanation:

Corresponding sides are proportional in similar triangles, so ...

  ZT/ZQ = KF/KB

  27/(2x +7) = 45/(4x+1)

  27(4x+1) = 45(2x +7) . . . cross-multiply

  3(4x +1) = 5(2x +7) . . . . divide by 9

  12x +3 = 10x +35 . . . . . eliminate parentheses

  2x = 32 . . . . . . . . . . . . . subtract 10x+3

  x = 16 . . . . . divide by 2

Then the length of BK is ...

  BK = 4x+1 = 4·16 +1

  BK = 65

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A student on a piano stool rotates freely with an angular speed of 2.85 rev/s . The student holds a 1.50 kg mass in each outstre
Vlad1618 [11]

Answer:r'=0.327 m

Step-by-step explanation:

Given

N=2.85 rev/s

angular velocity \omega =2\pi N=17.90 rad/s

mass of objects m=1.5 kg

distance of objects from stool r_1=0.789 m

Combined moment of inertia of stool and student =5.53 kg.m^2

Now student pull off his hands so as to increase its speed to 3.60 rev/s

\omega _2=2\pi N_2

\omega _2=2\pi 3.6=22.62 rad/s

Initial moment of inertia of two masses I_0=2mr_^2

I_0=2\times 1.5\times (0.789)^2=1.867

After Pulling off hands so that r' is the distance of masses from stool

I_0'=2\times 1.5\times (r')^2

Conserving angular momentum

I_1\omega =I_2\omega _2

(5.53+1.867)\cdot 17.90=(5.53+I_o')\cdot 22.62

I_0'=1.397\times 0.791

I_0'=5.851

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7 0
3 years ago
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jasenka [17]

y = A(Bx - C)ⁿ + D

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C is a shift to the right (or left if C is negative) → notice that Bx - C is "-C" so to take the opposite

D is a shift up (or down if D is negative)

when C = -3, it is a shift to the left 3 units

when D = -7, it is a shift down 7 units

Answer: B

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3 years ago
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Answer:x= -54.7

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