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Basile [38]
2 years ago
13

Please help with question ​

Mathematics
2 answers:
pav-90 [236]2 years ago
7 0

Applying precedence of operations, the result of the expression is of 161.

<h3>What is the precedence of operations?</h3>

Power operations are done before multiplication/division, which are also done before addition/subtraction.

Operations inside brackets or parenthesis also take precedence.

In this problem, the operation is:

[3 x 2^5 + 13 x (-2)] + 7[8 - (4 - 9)]

First the power:

[3 x 32 + 13 x (-2)] + 7[8 - (4 - 9)]

Now the multiplications on the first bracket, and the subtraction on the second:

[96 - 26] + 7[8 - (-5)]

Then, applying the parenthesis to the negative number, we have that:

[96 - 26] + 7[8 - (-5)] = 70 + 7 x 13 = 161.

More can be learned about precedence of operations at brainly.com/question/550188

#SPJ1

Alex Ar [27]2 years ago
3 0

\huge\text{Hey there!}

\mathsf{3 \times 2^5 + 13(-2)] + 7[8 - (4 - 9)]}

\mathsf{= 3\times32 + 13\times -2 + 7[8 - (4 - 9)] }

\mathsf{= 96 + 13\times -2 + 7(8 - (4 - 9))}

\mathsf{= 96 - 26 + 7(8 - (4 - 9))}

\mathsf{= 70 + 7(8 - (4 - 9))}

\mathsf{= 70 + 7(8 - (-5))}

\mathsf{= 70 + 7\times13}

\mathsf{= 70 + 91}

\mathsf{= 161}


\huge\text{Therefore, your answer should be: }

\huge\boxed{\frak{161}}\huge\checkmark


\huge\text{Good luck on your assignment \& enjoy your day!}


~\frak{Amphitrite1040:)}

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The given line segment has a midpoint at (3, 1).
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Answer:

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Step-by-step explanation:

The given line segment has a midpoint at (3, 1) and goes through (2, 4), (3, 1), and (4, -2). We can use any two of the three points to calculate the equation of the line. Let us use the points (2, 4) and (4, -2)

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\frac{y-y_1}{x-x_1}=\frac{y_2-y_1}{x_2-x_1}\\\frac{y-4}{x-2}=\frac{-2-4}{4-2}\\\frac{y-4}{x-2}=\frac{-6}{2}\\y-4=x-2(-3)\\y-4=-3x+6\\y=-3x+10

Comparing with the general equation of line: y = mx + c, the slope (m) = -3 and the intercept on the y axis (c) = 10

Two lines are said to be perpendicular if the product of their slope is -1. If the slope of line one is m1 and the slope of line 2 = m2, then the two lines are perpendicular if:

m_1m_2=-1.

Therefore The slope (m2) of the perpendicular bisector of y = -3x + 10 is:

m_1m_2=-1\\-3m_2=-1\\m_2=\frac{1}{3}

Since it is the  perpendicular bisector of the given line segment, it passes through the midpoint (3, 1). The equation of the perpendicular bisector is:

\frac{y-y_1}{x-x_1}=m\\\frac{y-1}{x-3}=\frac{1}{3}\\ y-1= \frac{1}{3}(x-3)\\ y-1=\frac{1}{3}x-1\\y=\frac{1}{3}x

the equation, in slope-intercept form, of the perpendicular bisector of the given line segment is y=\frac{1}{3}x

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