P=2(L+W) and P=34 so
2(L+W)=34
L+W=17 so we can say
L=17-W
A=LW using L from above
A=(17-W)W
A=17W-W^2 and A=30 so
30=17W-W^2
W^2-17W+30=0
W^2-2W-15W+30=0
W(W-2)-15(W-2)=0
(W-15)(W-2)=0
So the dimensions of the rectangle are 15 meters by 2 meters.
Probably the subsitution method
y=1/2x
subsitute that fr y
2x+3(1/2x)=28
2x+3/2x=28
times 2 both sides
4x+3x=56
7x=56
divide by 7 both sides
x=8
sub back
y=1/2x
y=1/2(8)
y=4
(x,y)
(8,4)
Step-by-step explanation:
your friend is closer to the school (b)
it's graph covers less area..