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3 years ago

Aj jar of sweets contains 5 yellow sweets, 4 red sweets, 8 green sweets 4 orange sweets and 3 white sweets.

Mathematics

2 answers:

LuckyWell [14K]3 years ago

7 0

Answer:

$\frac{9}{24}$

Step-by-step explanation:

Add all the sweets together ( that will be your denominator )

5+4+8+4+3= 24

The probability she will pick and yellow and orange ( add those numbers together)

Yellow + orange = Numerator

5+4=9

How you answer should be lay out :

$\frac{Orange+ yellow sweets}{Total amount of sweets}$

Alisiya [41]3 years ago

4 0

Answer:

9/24

Step-by-step explanation:

add the sweets (for denominator) 5+4+8+4+3 =24 then add yellow + orange (which is 9)

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00:04

01:32

Step-by-step explanation:

7 0

3 years ago

The sale price of a new compact disc player is $212 at a local discount store. At the store where this sale is going on, each ne

love history [14]

Answer:

6 CDs

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

For funcitons f(x)=2x+3 and g(x)=-3x-2, please find (f∘g)(-1)

ratelena [41]

Answer:

$\displaystyle (f\circ g)(-1) = 5$

Step-by-step explanation:

We are given the two functions:
$\displaystyle f(x) = 2x + 3\text{ and } g(x) = -3x - 2$

And we want to find:
$\displaystyle (f\circ g)(-1)$

Recall that this is equivalent to:
$\displaystyle (f\circ g)(-1) = f(g(-1))$

Hence, find g(-1):
$\displaystyle \begin{aligned} g(x) & = -3x - 2\\ \\ g(-1) & = -3(-1) - 2\\ \\ & = (3) - 2 \\ \\ & = 1 \end{aligned}$

Substitute:
$\displaystyle f(g(-1)) = f(1)$

Find f(1):

$\displaystyle \begin{aligned} f(x) & = 2x+ 3 \\ \\ f(1) & = 2(1) + 3 \\ \\ & = 5\end{aligned}$

In conclusion:
$\displaystyle (f\circ g)(-1) = 5$

5 0

3 years ago

MATHISLIF3 for uuuuuuuuuuuuuu

Kobotan [32]

____________________________

3 0

4 years ago

Simplify: 4 - (3 + 1)2 - 6 ÷ 2 + 4 Combine like terms: 7x3 + 2x - 5x2 + 6 + x + 9 + 3x3 + 12x2 Simplify: (2x5 - 3x2 + 4) - (x5 +

Svetach [21]

Answer:

Step-by-step explanation:

4-(3+1)^2-6/2+4

4-4^2-3+4

4-16-3+4

-12-3+4

-15+4

-11

-------------------------

7x^3+2x-5x^2+6+x+9+3x^3+12x^2

10x^3-5x^2+12x^2+2x+x+6+9

10x^3+7x^2+3x+15

-------------------------------

3x^2(4x^3-2x^2+7x-4)

12x^5-6x^4+21x^3-12x^2

--------------------------------------

6x^2+9x-7 when x=2

6(2)^2+9(2)-7

6(4)+18-7

24+18-7

42-7

------------------------------

3(x-y)^2+4y-6x+2

3(-1-3)^2+4(3)-6(-1)+2

3(-4)^2+12+6+2

3(16)+12+8

48+12+8

------------------------------

7x-5=23

7x=23+5

7x=28

x=28/7

x=4

---------------

7y-4+3y+6=9y+8

10y-4+6=9y+8

10y-9y+2=8

y+2=8

y=8-2=6

y=6

--------------------------

5(w-2)+6=3w-14

5w-10+6=3w-14

5w-4=3w-14

5w-3w-4=-14

2w-4=-14

2w=-14+4

2w=-10

w=-10/2

w=-5

----------------------

-4x+2<2x-6

-4x-2x+2<-6

-6x+2<-6

-6x<-6-2

-6x<-8

6x<8

x<8/6

x<4/3

x>4/3

8 0

3 years ago

Read 2 more answers