Explanation:
To solve this question, we will use the Clayperon Equation:
P.V = n.R.T
where:
P = 101.28 kPa
1 atm = 101,325 Pa
x atm = 101,280 Pa
x = 1 atm
V = 37.058 L
n = we don't know
R = 0.082 atm.L/K.mol
T = -139.88 ºC = -139.88+273.15 = 133.27 K
1*37.058 = n*0.082*133.27
n = 0.29 moles
Answer: 0.29 moles
Assuming the volume of the gas is measured at standard temperature and pressure, Then one mole of the Gas would occupy 22.4 liters.
Therefore, 1 liter is 1/224 moles
one mole of nitrogen 14 is 14
Therefore 1 liter of the nitrogen weighs 1/224×14
0.0625 grams
Answer:
The rates of decay of radioactive elements
Explanation:
The age of a rock in years is called its absolute age. Geologists find absolute ages by measuring the amount of certain radioactive elements in the rock. When rocks are formed, small amounts of radioactive elements usually get included.
Answer:
B- fission breaks apart nuclei; fusion puts them back together
