All categories

3 years ago

Which statement is most likely true about KOH?

Chemistry

2 answers:

LekaFEV [45]3 years ago

5 0

you need to include the statements

konstantin123 [22]3 years ago

3 0

Answer: Which statements

Explanation: It turns blue litmus red. or Hydrogen gas is highly flammable.

You might be interested in

Drag the description to the category

viktelen [127]

Answer:

Explanation:

5 0

3 years ago

On the periodic table, gold has the atomic number 79. This means that

Troyanec [42]

Answer:

it has 79 protons

Explanation:

the atomic number is equal to the number of protons an element has.

3 0

3 years ago

How does the gravitational force change as two objects move farther apart ?

Lyrx [107]

The gravitational force decreases

6 0

3 years ago

7 km is equal to: 700 m 0.7 m 7,000 m 70 m

Vitek1552 [10]

7000m is the answer as 1 km is 1000m ...so 7km multiplied by 1000m u get 7000 m...and always remember if u r converting a bigger unit to a smaller unit u multiply and if u r converting a smaller unit to a bigger unit u divide

3 0

4 years ago

Read 2 more answers

7) For the reaction 9A (g) + B (g)  5C(g) + 1/6 D (g), it takes 4 and a half minutes for the concentration of C to increase to

viva [34]

Answer: The correct option is, (C) 0.53

Explanation:

The given chemical reaction is:

$9A(g)+B(g)\rightarrow 5C(g)+\frac{1}{6}D(g)$

The rate of the reaction for disappearance of A and formation of C is given as:

$\text{Rate of disappearance of }A=-\frac{1}{9}\times \frac{\Delta [A]}{\Delta t}$

Or,

$\text{Rate of formation of }C=+\frac{1}{5}\times \frac{\Delta [C]}{\Delta t}$

where,

$\Delta C$ = change in concentration of C = 1.33 M

$\Delta t$ = change in time = 4.5 min

Putting values in above equation, we get:

$\frac{1}{9}\times \frac{\Delta [A]}{\Delta t}=\frac{1}{5}\times \frac{\Delta [C]}{\Delta t}$

$\frac{\Delta [A]}{\Delta t}=\frac{9}{5}\times \frac{\Delta [C]}{\Delta t}$

$\frac{\Delta [A]}{\Delta t}=\frac{9}{5}\times \frac{1.33M}{4.5min}$

$\frac{\Delta [A]}{\Delta t}=0.53M/min$

Thus, the decrease in A during this time interval is, 0.53

5 0

3 years ago