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Dmitrij [34]
3 years ago
15

How many milliliters of 0.25M H2SO4 can be prepared from 57 mL of a 3.0M solution of H2SO4?

Chemistry
1 answer:
DochEvi [55]3 years ago
5 0

Answer:

Why ? Because 1 molecule of H2SO4 gives 2 H+ ions per molecule while only one H+ ion is required to neutralize 1 molecule of KOH. So, 1 molecule of H2SO4 can neutralize 2 molecules of KOH. Hence, we would require 525 ml of 0.03 M H2SO4 to neutralize 525 ml of 0.06 M KOH. How will we prepare 525 ml of 0.03 M H2SO4 ?

Explanation:

Now, we have 0.025 M H2SO4 and we do not know how much volume we have.

We will use the standard N1 X V1 = N2 X V2 for this calculation.

N1=0.025 M; V1=unknown; N2=0.03 M and V2=525 ml.

So V1= (0.03 X 525)/(0.025) = 630 ml.

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Vinvika [58]

Answer: 2.9(10)^{7} ft

Explanation:

Firstly we need to know that 1 km=3280.84 ft, then we cam make the conversion:

8848 km \frac{3280.84 ft}{1 km}=29,028,872.32 ft This is the height of Mount Everest in feet

However, we can express it using scientific notation by counting to the left the decimal spaces:

29,028,872.32 ft \approx 2.9(10)^{7} ft

3 0
3 years ago
4.00 moles of CU(CN)2<br><br>Find the number of grams ​
UNO [17]

Hey there!

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Find the molar mass.

Cu: 1 x 63.546 = 63.546

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-----------------------------------

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The mass of one mole of Cu(CN)₂ is 115.706 grams.

We have 4 moles.

115.706 x 4 = 463

4.00 moles of Cu(CN)₂ has a mass of 463 grams.

Hope this helps!

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21. Draw Lewis structure
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Which of the following is true about metallic bonding?
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