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PilotLPTM [1.2K]
2 years ago
15

Help i will think about giving brainlest if correct

Mathematics
2 answers:
alexandr1967 [171]2 years ago
7 0

Answer:

I think the answer is A

Step-by-step explanation:

xenn [34]2 years ago
3 0

Answer:  I'm pretty sure the answer is B.

Step-by-step explanation: A lunar eclipse only occurs i'm pretty sure when the sun, moon, and the earth is directly in front of each other.

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Which set of numerical values represents the minimum, lower quartile, median, upper quartile, and maximum, in that order, of the
Nana76 [90]
51     53       55      58    60      so   the 4th one
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3 years ago
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Heidi solved the equation
Liono4ka [1.6K]

Answer:

Correct.

Step-by-step explanation:

3 0
2 years ago
NEED HELP ASAP (please and thank you)
solmaris [256]

Answer:

800

Step-by-step explanation:

i dont know how to explain. i just did the math. hope this helps.

it wouldnt be 600 because thats 1/2 of 1200 not 2/3.  

7 0
2 years ago
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Cheryl can travel 21.6 miles on one gallon of gas. how far can cheryl travel on 6.2 gallons of gas?
boyakko [2]
21.6 miles per gallon

Multiplied by 6.2 gallons 

21.6 * 6.2 = 133.92

Cheryl can travel 133.92 (or about 134) miles on 6.2 gal. of gas.

Hope that helped!
6 0
3 years ago
A biologist is studying the elk population in a county park. She starts with only 2 elk and observes that the number of elk trip
DochEvi [55]

Answer:

The expression that represents the population of elk is: \text{elk}(t) = 2*3^t. It'll take 6 years for the population to reach 1,458 individuals.

Step-by-step explanation:

Since the number of elks triples every year and starts at \text{elk}(0) = 2, then after the first year the population will be:

\text{elk}(1) = \text{elk}(0)*3 = 2*3

While on the second year, it'll be:

\text{elk}(2) = \text{elk}(1)*3 = 2*3*3 = 2*3^2

On the third year:

\text{elk}(3) = \text{elk}(2)*3 = 2*3^2*3 = 2*3^3

And so on, therefore the expression that describes the population of elk as the years passes is:

\text{elk}(t) = 2*3^t

If we want to know the number of years until the population reach 1,458 elk, we need to apply this value to the left side of the equation and solve for t.

1458 = 2*3^t\\3^t = \frac{1458}{2}\\3^t = 729\\ln(3^t) = ln(729)\\t*ln(3) = ln(729)\\t = \frac{ln(729)}{ln(3)} = 6

The population will reach 1,458 elk in 6 years.

8 0
3 years ago
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