By the term dilated we mean to say that the dimensions of the new polyhedron is increase to a certain size by that times. For the volume, this dilation scale should be cubed in order to determine the number of times the volume of new figure is larger than the original.
r = (1.5)³
= 3.375
Thus, the volume of the new prism is 3.375 times larger than the volume of the original prism.
Where are the quadratic equations?
Answer:
- False
- True
-- False
-- True
-- True
Step-by-step explanation:
The points are
,
,
,
and
---- missing from the question
Given

Required
Determine if each of the points would be on 
To do this, we simply substitute the value of x and of each point in
.
(a)
In this case;
and 
becomes




<em>The point </em>
<em> won't be on the graph because the corresponding value of y for </em>
<em> is </em>
<em></em>
(b) 
In this case;


becomes





<em>The point </em>
<em> would be on the graph because the corresponding value of y for </em>
is 
(c) 
In this case:

becomes





<em>The point </em>
<em> wouldn't be on the graph because the corresponding value of y for </em>
<em> is </em>
<em></em>
(d) 
In this case;

becomes


<em>The point </em>
<em> would be on the graph because the corresponding value of y for </em>
is 
(e)
In this case:
; 
becomes




<em>The point </em>
<em> would be on the graph because the corresponding value of y for </em>
is 
The next terms in the sequence will be multiplied by c, but the common ratio is still the same
example :
S = [1(3)^4 - 1]/ [3-1] = 80/2 - 40
Hope this helps
The answers would be 11, if you plug it in it would be 5(11)-7=48