Which of the following situations involve a permutation?

Mathematics

1 answer:

alina1380 [7]3 years ago

8 0

Answer:

A, B, E

Step-by-step explanation:

Permutations are involved when order matters, as in lane assignment, passwords, and seating charts.

When the end result is a "group of 10 students", "3 employees", or "4 cashiers", clearly order does not matter. One student, employee, or cashier is as good as another in these cases.

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Marcie cooked dinner for herself. The original recipe has a serving size of 4 and requires four and four fifths pounds of chicke

Margarita [4]

Answer:

1.2 pounds of chicken per serving.

Step-by-step explanation:

4 and 4/5 of pounds of chicken for serving of 4.

We can also write this as 4.8 pounds of chicken.

To find how much pound of chicken will be needed for a single serving we have to divide 4.8 by 4.

$\frac{4.8}{4} = 1.2 \: pounds \: of \: chicken$

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7 0

2 years ago

#82 will give brainliest to best answer!

Fofino [41]

Answer:

$\frac{6}{k-6}$

Step-by-step explanation:

First, we can factor all of the following equations to turn that weird, huge looking thing into $\frac{(k+6)(k-6)}{(k-6)(k-10)}$ ÷ $\frac{(k-6)^2}{k(k-6)}$ × $\frac{6(k-10)}{k(k + 6)}$ . We know that division is simply multiplication by the reciprocal, so that whole equation will turn into $\frac{(k+6)(k-6)}{(k-6)(k-10)}$ × $\frac{k(k-6)}{(k-6)^2}$ × $\frac{6(k-10)}{k(k+6)}$ . Now we can cancel out some values if they are both in the numerator and denominator, which will turn that still huge looking thing into $\frac{6}{k-6}$ which is our final answer, as it cannot be simplified further.