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3 years ago

What is the SEC?

Mathematics

2 answers:

Ronch [10]3 years ago

5 0

I believe it’s C!!!!

Murrr4er [49]3 years ago

4 0

Answer:

The answer is C!!

Step-by-step explanation:

I got it right on quiz edge2020

Have a great day <3

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Which graph represents the solution set for -4(1-×)<-12+2×?

sveta [45]

I will answer assuming that the equation is 4(1-x) < -12+2x

1) 4 - 4x < - 12 + 2x

2) 2x + 4x > 4 + 12

3) 6x > 16

4) x > 16 / 6

5) x > 8 / 3

So the graph is all the real numbers greater than 8/3 which may be represented by a straight line from 8/3 to the right toward infinity

//////////////////////→
---------|--------------|--------------|----------o-----|-------------->
0 1 2 8/3 3

3 0

4 years ago

An item is priced at $14.54. If the sales tax is 7%, what does the item cost including sales tax?

fredd [130]

...................................15.01

7 0

4 years ago

You have a coin that is not weighted evenly and therefore is not a fair coin. Assume the true probability of getting heads when

Alexandra [31]

Answer:

$X \sim Binom(n=157, p=0.52)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

And we want this probability:

$P(X$

And we can use the following Excel code to find the exact answer:

"=BINOM.DIST(75,157,0.52,TRUE)"

And we got 0.1633

The other way to solve the problem is using the normal approximation

We need to check the conditions in order to use the normal approximation.

$np=157*0.52=81.64 \geq 10$

$n(1-p)=157*(1-0.52)=75.36 \geq 10$

So we see that we satisfy the conditions and then we can apply the approximation.

If we appply the approximation the new mean and standard deviation are:

$E(X)=np=157*0.52=81.64$

$\sigma=\sqrt{np(1-p)}=\sqrt{157*0.52(1-0.52)}=6.26$

We want this probability:

$P(X$

And using the continuity correction we have this:

$P(X$

We can use the z score given by this formula $Z=\frac{x-\mu}{\sigma}$ .

$P(X< 76.5)=P(\frac{X-\mu}{\sigma}< \frac{76.5-81.64}{6.26})=P(Z < -0.821)=0.206$

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=157, p=0.52)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

And we want this probability:

$P(X$

And we can use the following Excel code to find the exact answer:

"=BINOM.DIST(75,157,0.52,TRUE)"

And we got 0.1633

The other way to solve the problem is using the normal approximation

We need to check the conditions in order to use the normal approximation.

$np=157*0.52=81.64 \geq 10$

$n(1-p)=157*(1-0.52)=75.36 \geq 10$

So we see that we satisfy the conditions and then we can apply the approximation.

If we appply the approximation the new mean and standard deviation are:

$E(X)=np=157*0.52=81.64$

$\sigma=\sqrt{np(1-p)}=\sqrt{157*0.52(1-0.52)}=6.26$

We want this probability:

$P(X$

And using the continuity correction we have this:

$P(X$

We can use the z score given by this formula $Z=\frac{x-\mu}{\sigma}$ .

$P(X< 76.5)=P(\frac{X-\mu}{\sigma}< \frac{76.5-81.64}{6.26})=P(Z < -0.821)=0.206$

4 0

4 years ago

Write thirty-five hundredths in decimal form

vfiekz [6]

Answer:

0.35i think if not please correct me

6 0

4 years ago

Read 2 more answers

A photograph was enlarge to a width of 15 inches. If the scale factor was 3/2, what was the width of the original photograph?

kati45 [8]

(3/2)W = 15
3W = 30
W = 10 inches

5 0

3 years ago