Maybe A? Cause the other ones stay the same size. Just guessing here
Equation F can be written as 5b+1=3b+4. <span>Both are equal to a and hence equal to each other. Hope this helped!</span>
Answer:
3.5
Step-by-step explanation:
<span>I think that there is no limitation about the combination amongst pants, shirts and shoes. This means that there are 3 different kinds and 11 pieces of them. So, the potential combinations are:
3^11 = 177147
A number which declares that Sophie has more than 48 choices. But this is an extraordinary number of choices taking into account the limitation that anytime the choice includes one kind of each. So, taking advance of the minimum number of pieces kind the 3 shirts in which one shirt will be choose at least, and then there is the following combination:
3^4+(3*4^4) = 768 outfit choices.
3^4 for shirts and punts
3 for shirts
4^4 for punts and shoes </span>
