Answer:
Step-by-step explanation:
40a²b = 2* 2 * 2 * 5 * a² * b = 2³ * 5 * a² * b
48ab⁴ = 2 * 2 * 2 * 2 * 3 * a *b⁴ = 2⁴ * 3 * a * b⁴
LCM = 2⁴ * 3 * 5 * a² * b⁴
= 16 * 3 * 5 * a² * b⁴
= 240a²b⁴
So divide factions ex: 6/2 divide 3/2 will bring down the first faction 6/2 then the always flip the second faction 2/3 to make it 2/3 the you have 6/2 divide 2/3, now you multiple 6/2 times 2/3 so how many times does 3 go in6 so the 3 will be 1 and the 6 will be 2 now 2 and 2 both will come 1 because 2 goes in both of them 1 time and the answer is 2/1
Answer:
The size limit for 15% of of six-year-old trout is 438.52 mm.
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 481 millimeters
Standard Deviation, σ = 41 millimeters
We are given that the distribution of mean length of six-year-old rainbow trout is a bell shaped distribution that is a normal distribution.
Formula:
We have to find the value of x such that the probability is 0.15
Calculation the value from standard normal z table, we have,
Thus, the size limit for 15% of of six-year-old trout is 438.52 mm.
Answer:
64
Step-by-step explanation:
You just have to add 35 and 29 and the answer is an integer cause it's a whole number.
Answer:
theta = 60 degrees
Step-by-step explanation:
tan theta = sqrt(3)
Take the inverse tan of each side
tan ^-1 tan theta = tan ^-1 (sqrt(3))
theta = 60 degrees
