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Fudgin [204]
2 years ago
12

1) Write 4 ratios, using the scaling down method, that are equivalent to 48 to 60

Mathematics
1 answer:
kow [346]2 years ago
6 0

Answer:

96 to 120

24 to 30

12 to 15

6 to 7.5

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Solve by using the substitution method. <br> 7x+3y=-37<br> -5x+y=39
AlladinOne [14]
Your final answer will be x=-7 and y=4. Included a pic. Sorry about the chicken scratch and torn up envelope.

8 0
3 years ago
Describe which of the two points lies on the graph of the line<br> 2x+2y=6<br> A,-4,5<br> B,6-3
Margaret [11]
B. 6, -3

2(6) + 2(-3) = 6

12 - 6 = 6

True

hope this helps
5 0
3 years ago
I WILL GIVE BRAINILEST AND 5 STAFS IF CORRECT
puteri [66]

Answer:

Part A: Describe the two factors in this expression. (4 points) The factors are (1) the constant coefficient 9 and (2) the binomial (7+2x).

Part B: How many terms are in each factor of this expression? (4 points) The first factor (multiplicand), 9, has one term. The second factor (multiplicand), (7+2x), has two terms (and is thus called a binomial).

Part C: What is the coefficient of the variable term? (2 points) The only such coefficient is 2.

6 0
3 years ago
PLS HELP WITH THIS ONE
olga2289 [7]

Answer:

460 ft^2 of carpet will be replaced

Step-by-step explanation:

You need to find the area of the room and then take away the area of the six bookcases

<u>Area of the room</u>

20*20=400ft^2

35-20=15ft

(15*20)/2=150ft^2

400+150=550ft^2 total room area

<u>Area of bookcases</u>

2.5*6*6=90ft^2 total bookcase area

<u>room area - bookcase area = carpet area</u>

550-90=460ft^2

4 0
2 years ago
Equilateral triangle ABC has an area of \sqrt{3}√ ​3 ​ ​​ . If the shaded region has an area of \piπK − \sqrt{3}√ ​3 ​ ​​ , what
Liono4ka [1.6K]

Answer:

The value of k = 4/3

Step-by-step explanation:

* Lets explain how to solve the problem

- An equilateral triangle ABC is inscribed in a circle N

- The area of the triangle is √3

- The shaded area is the difference between the area of the circle

  and the area of the equilateral triangle ABC

- The shaded are = k π - √3

- We need to find the value of k

* <u><em>At first lets find the length of the side of the Δ ABC</em></u>

∵ Δ ABC is an equilateral triangle

∴ Its area = √3/4 s² , where s is the length of its sides

∵ The area of the triangle = √3

∴ √3/4 s² = √3

- divide both sides by √3

∴ 1/4 s² = 1

- Multiply both sides by 4

∴ s² = 4 ⇒ take √ for both sides

∴ s = 2

∴ The length of the side of the equilateral triangle is 2

* <u><em>Now lets find the radius of the circle</em></u>

- In the triangle whose vertices are A , B and N the center of the circle

∵ AN and BN are radii

∴ AN = BN = r , where r is the radius of the circle

∵ The sides of the equilateral angles divides the circle into 3 equal

   arcs in measure where each arc has measure 360°/3 = 120°

∵ The measure of the central angle in a circle equal the measure

  of the its subtended arc arc

∵ ∠ANB is an central angle subtended by arc AB

∵ The measure of arc AB is 120°

∴ m∠ANB = 120°

- By using the cosine rule in Δ ANB

∵ AB = 2 , AN = BN = r , m∠ANB = 120°

∴ (2)^{2}=r^{2}+r^{2}-2(r)(r)cos(120)

∴ 4=r^{2}+r^{2}-2(r)(r)(-0.5)

∴ 4=r^{2}+r^{2}-(-r^{2})

∴ 4=r^{2}+r^{2}+r^{2}

∴ 4=3r^{2}

- Divide both sides by 3

∴ r^{2}=\frac{4}{3}

- Take square root for both sides

∴ r = 2/√3

* <u><em>Lets find the value of k</em></u>

∵ Area circle = πr²

∵ r = 2/√3

∴ Area circle = π(2/√3)² = (4/3)π

∵ Area shaded = area circle - area triangle

∵ Area triangle = √3

∴ Area shaded = (4/3) π - √3

∵ Area of the shaded part is π k - √3

- Equate the two expressions

∴ π k - √3 = (4/3) π - √3

∴ k = 4/3

* The value of k = 4/3

7 0
3 years ago
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