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MArishka [77]
3 years ago
9

A rectangle has dimensions 5 and one fourth

Mathematics
1 answer:
Mariulka [41]3 years ago
8 0
The area of one triangle is 28.875 inches.
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Quick help please!
Rudik [331]
I think that the answer is c but I'm not sure don't take my word for it if answer is wrong please don't be mad

3 0
3 years ago
2x -1 + x +1 = 180 <br> PLEASE SOLVE CORRECTLY
KiRa [710]

Answer:

x = 60

Step-by-step explanation:

Combine like terms on the left side of the equation: 2x + x = 3x; -1 + 1 = 0 so the total for the left side is just 3x. Now compare it to the full equation that you have left now, 3x = 180 now do 180/3 = 60

Hope this helps!

7 0
3 years ago
The ratio of damaged to undamaged toys was 3/17. If there were a total of 200 toys, how many
Natali5045456 [20]

Answer:

What I would do is find how many undamaged toys per 1 toy and then times that by 200.

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
(08.01)Which of the following statements shows a characteristic of a statistical question?
jonny [76]

It is not A,B, or D.

so it has to be C. wish I knew this when taking test.

let me know if it was right. I hope this is somewhat helpful.

4 0
3 years ago
Read 2 more answers
What is 3/2=9/10k im having troble lots rly
tigry1 [53]

Answer:

k=  5 over 3  =1.667

Step-by-step explanation:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                    (3)/(2)-((9)/(10)*k)=0

simplify 9/10

 3      9

 — -  (—— • k)  = 0  

 2     10

simplify 3/2

 3    9k

 — -  ——  = 0  

 2    10

   Find the Least Common Multiple

     The left denominator is :       2  

     The right denominator is :       10

Least Common Multiple:

     10

Calculate multipliers for the two fractions

   Denote the Least Common Multiple by  L.C.M  

   Denote the Left Multiplier by  Left_M  

   Denote the Right Multiplier by  Right_M  

   Denote the Left Deniminator by  L_Deno  

   Denote the Right Multiplier by  R_Deno  

  Left_M = L.C.M / L_Deno = 5

  Right_M = L.C.M / R_Deno = 1

Rewrite the two fractions into equivalent fractions

Two fractions are called equivalent if they have the same numeric value.

For example :  1/2   and  2/4  are equivalent,  y/(y+1)2   and  (y2+y)/(y+1)3  are equivalent as well.

To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.

  L. Mult. • L. Num.      3 • 5

  ——————————————————  =   —————

        L.C.M              10  

  R. Mult. • R. Num.      9k

  ——————————————————  =   ——

        L.C.M             10

Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

3 • 5 - (9k)     15 - 9k

————————————  =  ———————

     10            10  

Pull out like factors :

  15 - 9k  =   -3 • (3k - 5)

-3 • (3k - 5)

 —————————————  = 0  

      10      

When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

 -3•(3k-5)

 ————————— • 10 = 0 • 10

    10    

Now, on the left hand side, the  10  cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

  -3  •  (3k-5)  = 0

Solve :    -3   =  0

This equation has no solution.

A a non-zero constant never equals zero.

Solve  :    3k-5 = 0  

Add  5  to both sides of the equation :  

                     3k = 5

Divide both sides of the equation by 3:

                    k = 5/3 = 1.667

one solution was found

k = 5/3 = 1.667

hope it helps sry its so long

7 0
3 years ago
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