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3 years ago

A rectangle has dimensions 5 and one fourth

Mathematics

1 answer:

Mariulka [41]3 years ago

8 0

The area of one triangle is 28.875 inches.

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How do I change fractions to decimals?

Illusion [34]

Take your fraction and do this,,,, ex) with x and y as your fraction)

x/y=f/100
take 100/y and then ×x
ex)1/2=k/100
\/
100÷2
50×1
50/100
.50

ex)3/4=f/100

100/4
25×3=75/100
.75

ex)6/7=g/100
100/7
14.3×6
85.7/100
857/1000
.857

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3 years ago

DIRECTIONS: Type your answer in the space provided. The slope must be in fraction form.

Elanso [62]

DIRECTIONS: Type your answer in the space provided. The slope must be in fraction form.
What is the equation of the line parallel to the given line through the point (14,0)?

-4x - 7y = 14

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2 years ago

The police are concerned about speeding on Wayman Boulevard,

Iteru [2.4K]

Answer:

C) 20 Speeders

Step-by-step explanation:

5 divided by 2 is 2.5

there are 2.5 speeders per hour

over the span of 8 hours just multiply

8x2.5=20

5 0

3 years ago

948/10 to the third power

Fantom [35]

The answer is 0.948
Enjoy your day/night!

8 0

4 years ago

Suppose the time a child spends waiting at for the bus as a school bus stop is exponentially distributed with mean 7 minutes. De

Gala2k [10]

Answer:

The probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning is 0.148.

Step-by-step explanation:

Let the random variable X represent the time a child spends waiting at for the bus as a school bus stop.

The random variable X is exponentially distributed with mean 7 minutes.

Then the parameter of the distribution is, $\lambda=\frac{1}{\mu}=\frac{1}{7}$ .

The probability density function of X is:

$f_{X}(x)=\lambda\cdot e^{-\lambda x};\ x>0,\ \lambda>0$

Compute the probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning as follows:

$P(6\leq X\leq 9)=\int\limits^{9}_{6} {\lambda\cdot e^{-\lambda x}} \, dx$

$=\int\limits^{9}_{6} {\frac{1}{7}\cdot e^{-\frac{1}{7} \cdot x}} \, dx \\\\=\frac{1}{7}\cdot \int\limits^{9}_{6} {e^{-\frac{1}{7} \cdot x}} \, dx \\\\=[-e^{-\frac{1}{7} \cdot x}]^{9}_{6}\\\\=e^{-\frac{1}{7} \cdot 6}-e^{-\frac{1}{7} \cdot 9}\\\\=0.424373-0.276453\\\\=0.14792\\\\\approx 0.148$

Thus, the probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning is 0.148.

6 0

3 years ago