1.7(a+3)
2.5(x-1)
3.prime
4.3(5p-9)
5.3(15k-4)
6.8(3p+1)
7.47-5-2m+8m=42+6m=6(7+m)
8.2*10a-2*7b-10b-2a
20a-14b-10b-2a
18a-24b=6(3a-4b)
B,
as 32 is double 16, since 8 is double 4
425 / 50 = 8,5
There you go.
Answer:
The distribution is symmetric.
Step-by-step explanation:
<em>The distribution will be skew left, if the data is more distributed on left side of graph.</em>
<em>The distribution will be right left, if the data is more distributed on right side of graph.</em>
<em>The distribution is symmetric if from the center, the data is distributed symmetrically, equal increase or decrease on either side.</em>
<em>The distribution is uniform if the value of data remains constant throughout the graph.</em>
Above here, the from the center, the data decreases symmetrically on both the sides, same values of data for Cat-Rabbit pair and Dog-Mice pair.
Thus, distribution is symmetric.
Answer:
Volume = 16 unit^3
Step-by-step explanation:
Given:
- Solid lies between planes x = 0 and x = 4.
- The diagonals rum from curves y = sqrt(x) to y = -sqrt(x)
Find:
Determine the Volume bounded.
Solution:
- First we will find the projected area of the solid on the x = 0 plane.
A(x) = 0.5*(diagonal)^2
- Since the diagonal run from y = sqrt(x) to y = -sqrt(x). We have,
A(x) = 0.5*(sqrt(x) + sqrt(x) )^2
A(x) = 0.5*(4x) = 2x
- Using the Area we will integrate int the direction of x from 0 to 4 too get the volume of the solid:
V = integral(A(x)).dx
V = integral(2*x).dx
V = x^2
- Evaluate limits 0 < x < 4:
V= 16 - 0 = 16 unit^3
